(sin^(8)75^(@)-cos^(8)75^(@)) = -Turito

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Maths-

General

Easy

Question

$open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses$ =

$\frac{7 \sqrt{3}}{8}$
$\frac{3 \sqrt{3}}{8}$
$\frac{3 \sqrt{3}}{16}$
$\frac{7 \sqrt{3}}{16}$

The correct answer is: $fraction numerator 7 square root of 3 over denominator 16 end fraction$

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