Maths-

General

Easy

Question

# The cotangent function whose period is

- cot 2x
- cot 4x

Hint:

### In this question, we have to find the cotangent function whose period . As we know that the period of cot (k x) is , so, we can find the required cotangent function.

## The correct answer is:

### Period of cot (k x) =

given,

So, cotangent function whose period is .

### Related Questions to study

physics-

### Thirteen resistances each of resistance R are connected in the circuit as shown in the figure. The effective resistance between points A and B is

Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

### Thirteen resistances each of resistance R are connected in the circuit as shown in the figure. The effective resistance between points A and B is

physics-General

Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

physics-

### Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across The effective resistance across and the current through the arm will be

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

### Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across The effective resistance across and the current through the arm will be

physics-General

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

physics-

### In the circuit shown the value of I in ampere is

We can simplify the network as shown

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

### In the circuit shown the value of I in ampere is

physics-General

We can simplify the network as shown

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

physics-

### The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

The equation from the given graph can be written as,

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

### The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

physics-General

The equation from the given graph can be written as,

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

physics-

### The displacement-time graphs of two moving particles make angles of with the axis. The ratio of their velocities is

Slope of displacement time-graph is velocity

### The displacement-time graphs of two moving particles make angles of with the axis. The ratio of their velocities is

physics-General

Slope of displacement time-graph is velocity

Maths-

The minimum and maximum values of 3x are

As we know, if f(x)=a sin x+ b cos x

Then, range of f(x)

As f(x)= 8 cos 3x - 15 sin 3x

So, range of f(x)

Then, range of f(x)

As f(x)= 8 cos 3x - 15 sin 3x

So, range of f(x)

The minimum and maximum values of 3x are

Maths-General

As we know, if f(x)=a sin x+ b cos x

Then, range of f(x)

As f(x)= 8 cos 3x - 15 sin 3x

So, range of f(x)

Then, range of f(x)

As f(x)= 8 cos 3x - 15 sin 3x

So, range of f(x)

Physics-

### The graph between the displacement and for a particle moving in a straight line is shown in figure. During the interval and the acceleration of the particle is

,

Region shows that graph bending toward time axis acceleration is negative.

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

### The graph between the displacement and for a particle moving in a straight line is shown in figure. During the interval and the acceleration of the particle is

,

Physics-General

Region shows that graph bending toward time axis acceleration is negative.

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

Maths-

### Extreme Values:The range of

### Extreme Values:The range of

Maths-General

physics-

### What is the equivalent resistance between in the given circuit?

and are in series

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

### What is the equivalent resistance between in the given circuit?

physics-General

and are in series

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

are in parallel

and are in series

and are in parallel

and are in series

Now, and are in parallel

physics-

### The current in the 1 resistor shown in the circuit is

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

### The current in the 1 resistor shown in the circuit is

physics-General

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

physics-

### The current in the 1 resistor shown in the circuit is

In the given circuit 4 resistors are connected in parallel, this combination is connected in series with 1 resistance.

Also, R’’=2 +1 =3

From Ohm’s law,

Also, R’’=2 +1 =3

From Ohm’s law,

### The current in the 1 resistor shown in the circuit is

physics-General

Also, R’’=2 +1 =3

From Ohm’s law,

physics-

### The total current supplied to the given circuit by the battery is

The equivalent circuit of the given circuit is as shown

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

### The total current supplied to the given circuit by the battery is

physics-General

The equivalent circuit of the given circuit is as shown

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

Resistances 6 and 2 are in parallel

Resistances

Resistances 3 and 3 are in parallel

The current,

physics-

### A current of 2A flows in an electric circuit as shown in figure. The potential difference, in volts( are potentials at R and S respectively) is

Current through each arm

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

### A current of 2A flows in an electric circuit as shown in figure. The potential difference, in volts( are potentials at R and S respectively) is

physics-General

Current through each arm

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

PRQ and PSQ=1A

From Eqs. (i) and (ii), we get

physics-

### A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

### A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

physics-General

Resistance in the arms AC and BC are in series,

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

∴ R’=3+3=6

Now, R’ and 3 are in parallel,

Now, V=IR

physics-

### The equivalent resistance between the points A and B will be (each resistance is

15 )

The circuit can be shown as given below

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

### The equivalent resistance between the points A and B will be (each resistance is

15 )

physics-General

The circuit can be shown as given below

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B

The equivalent resistance between D and C.

Now, between A and B, the resistance of upper part ADCB,

Between A and B, the resistance of middle part AOB

Therefore, equivalent resistance between A and B