Maths-
General
Easy
Question
The period of
is

- 1
- 2

Hint:
In this question, we have to find the period of
and we know, period of sin kx =
. Firstly, we will find the period of the numerator and denominator and using which we can get the required period of function given.
The correct answer is: 1
f(x)=
Period of sin kx =
In numerator,
period of sin (
)=
In denominator,
period of sin (
)=
So, the period of f(x) is 1.
Related Questions to study
Maths-
Period of tan 4x+sec 4x is
f(x)= tan 4x + sec 4x
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Period of tan 4x+sec 4x is
Maths-General
f(x)= tan 4x + sec 4x
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Maths-
The cotangent function whose period
is
Period of cot (k x) = 
given,
So, cotangent function whose period is
.
given,
So, cotangent function whose period is
The cotangent function whose period
is
Maths-General
Period of cot (k x) = 
given,
So, cotangent function whose period is
.
given,
So, cotangent function whose period is
physics-
Thirteen resistances each of resistance R
are connected in the circuit as shown in the figure. The effective resistance between points A and B is

Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.
Now, there are four triangles
Effective resistance of each triangle



Now the given circuit reduced to

Therefore, effective resistance between A and B,


Now, there are four triangles
Effective resistance of each triangle
Now the given circuit reduced to

Therefore, effective resistance between A and B,
Thirteen resistances each of resistance R
are connected in the circuit as shown in the figure. The effective resistance between points A and B is

physics-General
Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.
Now, there are four triangles
Effective resistance of each triangle



Now the given circuit reduced to

Therefore, effective resistance between A and B,


Now, there are four triangles
Effective resistance of each triangle
Now the given circuit reduced to

Therefore, effective resistance between A and B,
physics-
Six resistors, each of value 3
are connected as shown in the figure. A cell of emf 3V is connected across
The effective resistance across
and the current through the arm
will be

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6
are in parallel

R’’’=3
Now, R’’’ and 3
resistances are in parallel


Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be


We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
Similarly, for arms CF and FE, R’’=6
R’’’=3
Now, R’’’ and 3
Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
Six resistors, each of value 3
are connected as shown in the figure. A cell of emf 3V is connected across
The effective resistance across
and the current through the arm
will be

physics-General
The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6
are in parallel

R’’’=3
Now, R’’’ and 3
resistances are in parallel


Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be


We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
Similarly, for arms CF and FE, R’’=6
R’’’=3
Now, R’’’ and 3
Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
physics-
In the circuit shown the value of I in ampere is

We can simplify the network as shown

So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.

Now, from the circuit (b),
4I’ =6I

But
=I+I’




So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But
In the circuit shown the value of I in ampere is

physics-General
We can simplify the network as shown

So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.

Now, from the circuit (b),
4I’ =6I

But
=I+I’




So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But
physics-
The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

The
equation from the given graph can be written as,


Substituting
from Eq. (i), we get


Thus,
graph is a straight line with positive slope and negative intercept.
Substituting
Thus,
The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

physics-General
The
equation from the given graph can be written as,


Substituting
from Eq. (i), we get


Thus,
graph is a straight line with positive slope and negative intercept.
Substituting
Thus,
physics-
The displacement-time graphs of two moving particles make angles of
with the
axis. The ratio of their velocities is

Slope of displacement time-graph is velocity


The displacement-time graphs of two moving particles make angles of
with the
axis. The ratio of their velocities is

physics-General
Slope of displacement time-graph is velocity


Maths-
The minimum and maximum values of 3x are
As we know, if f(x)=a sin x+ b cos x
Then, range of f(x)
As f(x)= 8 cos 3x - 15 sin 3x

So, range of f(x)
Then, range of f(x)
As f(x)= 8 cos 3x - 15 sin 3x
So, range of f(x)
The minimum and maximum values of 3x are
Maths-General
As we know, if f(x)=a sin x+ b cos x
Then, range of f(x)
As f(x)= 8 cos 3x - 15 sin 3x

So, range of f(x)
Then, range of f(x)
As f(x)= 8 cos 3x - 15 sin 3x
So, range of f(x)
Physics-
The graph between the displacement
and
for a particle moving in a straight line is shown in figure. During the interval
and
the acceleration of the particle is

, 
Region
shows that graph bending toward time axis
acceleration is negative.
Region
shows that graph is parallel to time axis
velocity is zero. Hence acceleration is zero.
Region
shows that graph is bending towards displacement axis
acceleration is positive.
Region
shows that graph having constant slope
velocity is constant. Hence acceleration is zero
Region
Region
Region
The graph between the displacement
and
for a particle moving in a straight line is shown in figure. During the interval
and
the acceleration of the particle is

, 
Physics-General
Region
shows that graph bending toward time axis
acceleration is negative.
Region
shows that graph is parallel to time axis
velocity is zero. Hence acceleration is zero.
Region
shows that graph is bending towards displacement axis
acceleration is positive.
Region
shows that graph having constant slope
velocity is constant. Hence acceleration is zero
Region
Region
Region
Maths-
Extreme Values:The range of 
Extreme Values:The range of 
Maths-General
physics-
What is the equivalent resistance between
in the given circuit?


Now,
What is the equivalent resistance between
in the given circuit?

physics-General

Now,
physics-
The current in the 1
resistor shown in the circuit is

In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
The current in the 1
resistor shown in the circuit is

physics-General
In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
physics-
The current in the 1
resistor shown in the circuit is

In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
The current in the 1
resistor shown in the circuit is

physics-General
In the given circuit 4
resistors are connected in parallel, this combination is connected in series with 1
resistance.



Also, R’’=2
+1
=3
From Ohm’s law,


Also, R’’=2
From Ohm’s law,
physics-
The total current supplied to the given circuit by the battery is

The equivalent circuit of the given circuit is as shown

Resistances 6
and 2
are in parallel

Resistances

Resistances 3
and 3
are in parallel

The current,


Resistances 6
Resistances
Resistances 3
The current,
The total current supplied to the given circuit by the battery is

physics-General
The equivalent circuit of the given circuit is as shown

Resistances 6
and 2
are in parallel

Resistances

Resistances 3
and 3
are in parallel

The current,


Resistances 6
Resistances
Resistances 3
The current,
physics-
A current of 2A flows in an electric circuit as shown in figure. The potential difference
, in volts(
are potentials at R and S respectively) is

Current through each arm
PRQ and PSQ=1A


From Eqs. (i) and (ii), we get

PRQ and PSQ=1A
From Eqs. (i) and (ii), we get
A current of 2A flows in an electric circuit as shown in figure. The potential difference
, in volts(
are potentials at R and S respectively) is

physics-General
Current through each arm
PRQ and PSQ=1A


From Eqs. (i) and (ii), we get

PRQ and PSQ=1A
From Eqs. (i) and (ii), we get