Question

# The ratio of the lengths of the parallel sides of a trapezium is 3:2. The shortest distance between them is 15cm. If the area of the trapezium is 450 sq. cm. Find the sum of the lengths of the parallel sides ?

Hint:

### let the length of parallel sides be x and y (x>y).Given ratio of x:y = 3:2

Substitute the equation in the formula area of trapezium = ½ × (height)(sum of lengths

of parallel side) and equate to find x

## The correct answer is: 60 cm

### Ans :- 60 cm

Explanation :-

Step 1:- Find the equation between x and y and find the sum of lengths of parallel sides in terms of y.

let the length of parallel sides be x and y (x>y).

Given ratio of x:y = 3:2

Sum of lengths of parallel sides =

Step 2:-substitute the values in the area formula find x

Given area of trapezium = 450 sq.cm

Altitude (or) height = 15 cm

area of trapezium = ½ × (height)(sum of lengths of parallel side)

We know Sum of lengths of parallel sides =

So, Sum of lengths of parallel sides = 60 cm.

Therefore, Sum of lengths of parallel sides is 60 cm.

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