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    General
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    Maths-

    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x 10 to the power of x minus x over denominator 1 minus cos space x end fraction equals

    Maths-General

    1. 4 log space 10
    2. log space 10
    3. 2 log space 10
    4. 3 log space 10

      Answer:The correct answer is: 2 log space 10

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      L t subscript n not stretchy rightwards arrow straight infinity end subscript fraction numerator n open parentheses 1 cubed plus 2 cubed plus midline horizontal ellipsis times plus n cubed close parentheses squared over denominator open parentheses 1 squared plus 2 squared plus midline horizontal ellipsis plus n squared close parentheses cubed end fraction equals

      L t subscript n not stretchy rightwards arrow straight infinity end subscript fraction numerator n open parentheses 1 cubed plus 2 cubed plus midline horizontal ellipsis times plus n cubed close parentheses squared over denominator open parentheses 1 squared plus 2 squared plus midline horizontal ellipsis plus n squared close parentheses cubed end fraction equals

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      If fraction numerator b over denominator c plus a end fraction plus fraction numerator c over denominator a plus b end fraction equals 1then

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      L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x left parenthesis 1 plus a cos invisible function application x right parenthesis minus b sin invisible function application x over denominator x cubed end fraction equals 1 text  then  end text straight a equals comma straight b equals

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      Lt subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator 1 over denominator sin squared begin display style space end style x end fraction minus fraction numerator 1 over denominator sinh squared space x end fraction equals

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      The quadratic equation whose roots are I and m where l =lim for theta not stretchy rightwards arrow 0 of   open parentheses fraction numerator 3 sin space theta minus 4 sin cubed space theta over denominator theta end fraction close parentheses m equals lim for theta not stretchy rightwards arrow 0 of   open parentheses fraction numerator 2 tan space theta over denominator theta open parentheses 1 minus tan squared space theta close parentheses end fraction close parentheses is

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      text  If  end text a greater than 0 text  and  end text L subscript x not stretchy rightwards arrow a end subscript fraction numerator a to the power of x minus x to the power of 4 over denominator x to the power of x minus a to the power of a end fraction equals negative1, then a=

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      In straight triangle A B C comma left parenthesis a plus b plus c right parenthesis open parentheses tan invisible function application A over 2 plus tan invisible function application B over 2 close parentheses equals

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      L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of x minus e to the power of in space x end exponent over denominator 2 left parenthesis x minus sin space x right parenthesis end fraction equals

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      Lt subscript x not stretchy rightwards arrow straight infinity end subscript space open parentheses fraction numerator x plus a over denominator x plus b end fraction close parentheses to the power of x plus b end exponent equals

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      Lt subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses fraction numerator x plus 5 over denominator x plus 2 end fraction close parentheses to the power of x plus 3 end exponent equals

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