Maths-

General

Easy

Question

# What are all the possible values of b for which is it factorable using only integer coefficients and constant?

Hint:

### to be factorable we need to write the middle term as a sum of factors of 1 st and last term.

## The correct answer is: {-23,-10,-5,-2,2,5,10,23} are all possible values of b.

### Ans:- {-23,-10,-5,-2,2,5,10,23} are all possible values of b.

Given, is it factorable so be must be sum of factors of (-8)(3)

Factors of -24 are

(1,-24) b can be -24 + 1 = -23

(2,-12) b can be -12 + 2 = -10

(3,-8) b can be -8 + 3 = -5

(4,-6) b can be 4 - 6 = -2

(6,-4) b can be 6 - 4 = 2

(8,-3) b can be 8 - 3 = 5

(12,-2) b can be 12 - 2 = 10

(24,-1) b can be 24 - 1 = 23

So, there are 8 possible values of b they are {-23, -10, -5, -2, 2, 5, 10, 23}

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