Maths-
General
Easy

Question

What are all the possible values of b for which 3 x squared plus b x minus 8 is it factorable using only integer coefficients and constant?

hintHint:

to be factorable we need to write the middle term as a sum of factors of 1 st and last term.

The correct answer is: {-23,-10,-5,-2,2,5,10,23} are all possible values of b.


    Ans:-  {-23,-10,-5,-2,2,5,10,23} are all possible values of b.
    Given, 3 x squared plus b x minus 8 is it factorable  so be must be sum of factors of (-8)(3)
    Factors of -24 are
    (1,-24) not stretchy rightwards double arrow b can be -24 + 1 = -23
    (2,-12) not stretchy rightwards double arrow b can be -12 + 2 = -10
    (3,-8) not stretchy rightwards double arrow b can be -8 + 3 = -5
    (4,-6) not stretchy rightwards double arrow b can be 4 - 6 = -2
    (6,-4) not stretchy rightwards double arrow b can be 6 - 4 = 2
    (8,-3) not stretchy rightwards double arrow b can be 8 - 3 = 5
    (12,-2) not stretchy rightwards double arrow b can be 12 - 2 = 10
    (24,-1) not stretchy rightwards double arrow b can be 24 - 1 = 23
    So, there are 8 possible values of b they are {-23, -10, -5, -2, 2, 5, 10, 23}

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