Maths-
Least common multiple for 12 and 5 is
Maths-General
- 40
- 80
- 20
- 60
Answer:The correct answer is: 60As 12 and 5 are co-prime, there product will be the LCM
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Related Questions to study
Maths-
If all the sides of triangle ,so the triangle is called __________ triangle:
If all the sides of a triangle is equal, then its called an equilateral
Triangle.
Triangle.
If all the sides of triangle ,so the triangle is called __________ triangle:
Maths-General
If all the sides of a triangle is equal, then its called an equilateral
Triangle.
Triangle.
Maths-
What is LCM of 4 and 6.
LCM of 4 & 6= 2*2*3 = 12
What is LCM of 4 and 6.
Maths-General
LCM of 4 & 6= 2*2*3 = 12
Maths-
The area of a rectangular park is 1500 sq m. If the lenth is 50m, find its width. Also find the perimeter of the park.
Area of rectangular park = 1500 sq m
Length = 50m
Bredth of the park= (1500/50)
= 30m
Perimeter =2*(l+b)
= 2*(50 + 30)
=2* 80
= 160m
Length = 50m
Bredth of the park= (1500/50)
= 30m
Perimeter =2*(l+b)
= 2*(50 + 30)
=2* 80
= 160m
The area of a rectangular park is 1500 sq m. If the lenth is 50m, find its width. Also find the perimeter of the park.
Maths-General
Area of rectangular park = 1500 sq m
Length = 50m
Bredth of the park= (1500/50)
= 30m
Perimeter =2*(l+b)
= 2*(50 + 30)
=2* 80
= 160m
Length = 50m
Bredth of the park= (1500/50)
= 30m
Perimeter =2*(l+b)
= 2*(50 + 30)
=2* 80
= 160m
Maths-
-3/-8 is
Positive rational number
-3/-8 is
Maths-General
Positive rational number
Maths-
¼ litre of milk cost Rs 15/2 . Find the cost of 9/2 litre of milk.
Cost of ¼ litre milk= Rs 15/2
Cost of 1 litre milk =Rs (15/2) /(1/4)
=Rs (15/2 *4/1)
= Rs 30
Cost of 9/2 litre of milk =30 * 9/2
= (30*9)/2
= Rs 135
Cost of 1 litre milk =Rs (15/2) /(1/4)
=Rs (15/2 *4/1)
= Rs 30
Cost of 9/2 litre of milk =30 * 9/2
= (30*9)/2
= Rs 135
¼ litre of milk cost Rs 15/2 . Find the cost of 9/2 litre of milk.
Maths-General
Cost of ¼ litre milk= Rs 15/2
Cost of 1 litre milk =Rs (15/2) /(1/4)
=Rs (15/2 *4/1)
= Rs 30
Cost of 9/2 litre of milk =30 * 9/2
= (30*9)/2
= Rs 135
Cost of 1 litre milk =Rs (15/2) /(1/4)
=Rs (15/2 *4/1)
= Rs 30
Cost of 9/2 litre of milk =30 * 9/2
= (30*9)/2
= Rs 135
Maths-
11 divided by 1/3
11 ÷1/3 = 11 x 3/1 = 33
11 divided by 1/3
Maths-General
11 ÷1/3 = 11 x 3/1 = 33
Maths-
What is the lowest term of 24/40
24 and 40 both are divisible by 8
24 /8
40/8
{24/8 = 3 and 40/8 = 5}
Lowest term =3/5
24 /8
40/8
{24/8 = 3 and 40/8 = 5}
Lowest term =3/5
What is the lowest term of 24/40
Maths-General
24 and 40 both are divisible by 8
24 /8
40/8
{24/8 = 3 and 40/8 = 5}
Lowest term =3/5
24 /8
40/8
{24/8 = 3 and 40/8 = 5}
Lowest term =3/5
Maths-
Himani saves Rs 700 a month and pratibha saves Rs 900 a month. Find the ratio in their savings.
Himani’s ratio = Rs 700 per month
Pratibha’s ratio = Rs 900 per month
Ratio of their savings = 700/900
= (700/100) / (900/100)
=7/9
= 7:9
Pratibha’s ratio = Rs 900 per month
Ratio of their savings = 700/900
= (700/100) / (900/100)
=7/9
= 7:9
Himani saves Rs 700 a month and pratibha saves Rs 900 a month. Find the ratio in their savings.
Maths-General
Himani’s ratio = Rs 700 per month
Pratibha’s ratio = Rs 900 per month
Ratio of their savings = 700/900
= (700/100) / (900/100)
=7/9
= 7:9
Pratibha’s ratio = Rs 900 per month
Ratio of their savings = 700/900
= (700/100) / (900/100)
=7/9
= 7:9
Maths-
Find the range of the following data: 2,8,3,9,1,0
Range = highest value – smallest value = 9-0 =9
Find the range of the following data: 2,8,3,9,1,0
Maths-General
Range = highest value – smallest value = 9-0 =9
Maths-
What is 8 in roman numeral
V= 5 adding 3 times I will be 8
What is 8 in roman numeral
Maths-General
V= 5 adding 3 times I will be 8
Maths-
Find the area of a given triangle whose perimeter is equal to 26cm .10 cm
Perimeter= 26cm
Height=10cm
Hypotenuse=12cm
Area=?
Perimeter of triangle=sum of sides
26=10+12+ b
26=22+b
26-22=b
4cm=b
Area=1/2*base*height
=1\2 * 4*10= 20 sq. cm
Height=10cm
Hypotenuse=12cm
Area=?
Perimeter of triangle=sum of sides
26=10+12+ b
26=22+b
26-22=b
4cm=b
Area=1/2*base*height
=1\2 * 4*10= 20 sq. cm
Find the area of a given triangle whose perimeter is equal to 26cm .10 cm
Maths-General
Perimeter= 26cm
Height=10cm
Hypotenuse=12cm
Area=?
Perimeter of triangle=sum of sides
26=10+12+ b
26=22+b
26-22=b
4cm=b
Area=1/2*base*height
=1\2 * 4*10= 20 sq. cm
Height=10cm
Hypotenuse=12cm
Area=?
Perimeter of triangle=sum of sides
26=10+12+ b
26=22+b
26-22=b
4cm=b
Area=1/2*base*height
=1\2 * 4*10= 20 sq. cm
Maths-
GCF of 28 and 54
Factors of 28 = 1,2,7,14,28
Factors of 54 = 1,2,3,6,9,27,54
Greatest common factor = 2
Factors of 54 = 1,2,3,6,9,27,54
Greatest common factor = 2
GCF of 28 and 54
Maths-General
Factors of 28 = 1,2,7,14,28
Factors of 54 = 1,2,3,6,9,27,54
Greatest common factor = 2
Factors of 54 = 1,2,3,6,9,27,54
Greatest common factor = 2
Maths-
What is 8 x 1/32
8x 1/32 = 8/32 = ¼
What is 8 x 1/32
Maths-General
8x 1/32 = 8/32 = ¼
Maths-
convert 17 into roman numerals.
17=10+7
=X + VII
=XVII
=X + VII
=XVII
convert 17 into roman numerals.
Maths-General
17=10+7
=X + VII
=XVII
=X + VII
=XVII
Maths-
What is prime factorization of 28
2x2x7
What is prime factorization of 28
Maths-General
2x2x7