Maths-
General
Easy

Question

Vihan’s class is making care packages to give to victims of a natural disaster. Vihan packs one box in 5 minutes and has already packed 12 boxes. His friend Simaran packs one box in 7 minutes and has already packed 18 boxes. How many more minutes does each need to work in order to have packed the same number of boxes?

hintHint:

○ Form the equation according to given information..
○ Take variable values as x or any alphabet.
○ Solve the equation to get value of x.

The correct answer is: ⇒ x = 105


    ○ Given:
    rightwards double arrowVihan packs one box in 5 minutes and has already packed 12 boxes.
    rightwards double arrowSimaran packs one box in 7 minutes and has already packed 18 boxes.
    ○ Step 1:
    ○ Let the number of minutes they work be x minutes.
    First consider case of Vihan:
    5 minutes  = 1 box
    1 minutes = 1 fifth box
    So, in
    x minutes = x over 5 box
    Hence, at end of x minutes number of boxes made by Vihan will be
    12 + x over 5 box
    Now, considet case of Simaran:
    7 minutes  = 1 box
    1 minutes = 1 over 7 box
    So, in
    x minutes = x over 7 box
    Hence, at end of x minutes number of boxes made by Vihan will be
    rightwards double arrow18 + x over 7 box
    ○ Step 2:
    ○ Now equate the no. of boxes made by both:
    rightwards double arrow12 + x over 5 = 18 + x over 7
    rightwards double arrowx over 5- x over 7 = 18 - 12
    rightwards double arrowfraction numerator 7 x space minus space 5 x over denominator 35 end fraction= 6
    rightwards double arrow7x -5x = 6  35
    rightwards double arrow2x = 210
    rightwards double arrowx = 210 over 2
    rightwards double arrowx = 105
    • Final Answer:
    Hence, after 105 minutes of work they will have same number of boxes made.

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