Physics-
General
Easy

Question

In the diagram shown, the separation between the slit is equal to 3 lambda comma where lambda is the wavelength of the light incident on the plane of the slits A thin film of thickness 3 lambda and refractive index 2 has been placed in the front of the upper slit. Assuming D greater than greater than lambda the distance of the central maxima on the screen from O is:

  1. D    
  2. lambda d divided by D    
  3. lambda D divided by d    
  4. None    

The correct answer is: None


    There will be only 5 maxima on screen. Hence fringe width looses its meaning i.e., they are non uniform. Hence calculation must be done using geometry.

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