C_(6)h_(5)nh_(2)hcl^(n_(2)no_(2))xlongrightarrow^(cu_(2)(cn_(2)-Turito

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Chemistry-

General

Easy

Question

$straight C subscript 6 straight H subscript 5 NH subscript 2 HCl with rightwards arrow with NaNO subscript 2 on top on top X rightwards arrow with Cu subscript 2 left parenthesis CN right parenthesis subscript 2 on top Y rightwards arrow with straight H subscript 2 straight O divided by straight H to the power of plus on top Z$ Z is identified as

$C_{6} H_{5} - N H - C H_{3}$
$C_{6} H_{5} - C O O H$
$C_{6} H_{5} - C H_{2} - N H_{2}$
$C_{6} H_{5} - C H_{2} C O O H$

The correct answer is: $C subscript 6 H subscript 5 minus C O O H$

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