Chemistry-

General

Easy

### Question

#### Electronic configuration has violated:

- Hund’s rule
- Pauli’s principle
- Aufbau principle
- (n+l)rule

#### The correct answer is: Hund’s rule

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### Related Questions to study

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_{36}Kr has the electron configuration (_{18}Ar) 4s^{2 }3d^{10 }4p^{6}.The39thelectronwillgo into which one of the following sub-levels:

_{36}Kr has the electron configuration (_{18}Ar) 4s^{2 }3d^{10 }4p^{6}.The39thelectronwillgo into which one of the following sub-levels:

chemistry-General

biology

#### The figure below shows the structure of a mitochondrion with its four parts labelled (A), (B),(C). and (D) Select the part correctly matched with its function.

#### The figure below shows the structure of a mitochondrion with its four parts labelled (A), (B),(C). and (D) Select the part correctly matched with its function.

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#### n, l and m values of an electron in 3pyorbital are:

#### n, l and m values of an electron in 3pyorbital are:

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#### If l=3 then type and number of orbital is:

#### If l=3 then type and number of orbital is:

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#### An electron is in one of 4dorbital.Which of the following orbital quantum number value is not possible:

#### An electron is in one of 4dorbital.Which of the following orbital quantum number value is not possible:

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#### For the azimuthal quantum number(l),the total number of magnetic quantum number is

given by:

#### For the azimuthal quantum number(l),the total number of magnetic quantum number is

given by:

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biology

#### Important site for formation of glycoproteins and glycolipids is :

#### Important site for formation of glycoproteins and glycolipids is :

biologyGeneral

maths-

#### Area of the circle in which a chord of length makes an angle p/2 at the centre is

Let AB be the chord of length , O be the centre of the circle and let OC be the perpendicular from O on AB. Then AC = BC =

In DOBC, OB = BC cosec 45° =

\ Area of the circle = p (OB)

Hence (c) is the correct answer.

In DOBC, OB = BC cosec 45° =

\ Area of the circle = p (OB)

^{2}= p.Hence (c) is the correct answer.

#### Area of the circle in which a chord of length makes an angle p/2 at the centre is

maths-General

Let AB be the chord of length , O be the centre of the circle and let OC be the perpendicular from O on AB. Then AC = BC =

In DOBC, OB = BC cosec 45° =

\ Area of the circle = p (OB)

Hence (c) is the correct answer.

In DOBC, OB = BC cosec 45° =

\ Area of the circle = p (OB)

^{2}= p.Hence (c) is the correct answer.

maths-

#### Equation of a circle with centre (4, 3) touching the circle is

Let the circle touching the circle x

The equation of the common tangent is S

i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

Hence (d) are the correct answers.

^{2 }+ y^{2}= 1, be x^{2 }+ y^{2 }– 8x – 6y + k = 0,The equation of the common tangent is S

_{1}– S_{2}= 0i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

^{2}+y^{2}= 1.Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

^{2}+y^{2}–8x–6y+9 = 0 and x^{2}+y^{2}–8x–6y–11 = 0Hence (d) are the correct answers.

#### Equation of a circle with centre (4, 3) touching the circle is

maths-General

Let the circle touching the circle x

The equation of the common tangent is S

i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

Hence (d) are the correct answers.

^{2 }+ y^{2}= 1, be x^{2 }+ y^{2 }– 8x – 6y + k = 0,The equation of the common tangent is S

_{1}– S_{2}= 0i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

^{2}+y^{2}= 1.Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

^{2}+y^{2}–8x–6y+9 = 0 and x^{2}+y^{2}–8x–6y–11 = 0Hence (d) are the correct answers.

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#### The four quantum numbers for the valence shell electron of last electron of sodium (Z=11) is

#### The four quantum numbers for the valence shell electron of last electron of sodium (Z=11) is

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#### If n=3,then which value of ‘ι’is correct:

#### If n=3,then which value of ‘ι’is correct:

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#### In an electronic transition atom cannot emit:

#### In an electronic transition atom cannot emit:

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biology

#### Which stages of cell division do the following figures A and B represent respectively ?

#### Which stages of cell division do the following figures A and B represent respectively ?

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biology

#### Given below is a schematic break-up of the phases/stages of cell cycle Which one of the following is the correct indication of the state/phase in the cell cycle -

#### Given below is a schematic break-up of the phases/stages of cell cycle Which one of the following is the correct indication of the state/phase in the cell cycle -

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chemistry-

#### Which of the following transition neither shows absorption nor emission of energy incase of Hydrogen atom:

#### Which of the following transition neither shows absorption nor emission of energy incase of Hydrogen atom:

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