Chemistry-
General
Easy
Question
n, l and m values of an electron in 3pyorbital are:
- n=3;l=1 and m=1
- n=3;l=1andm=–1
- Bothe1and2arecorrect
- None of these
The correct answer is: Bothe1and2arecorrect
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i.e. 8x + 6y–1–k = 0
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This is a tangent to the circle x2+y2 = 1.
Hence ± 1 =
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Therefore the circles are x2+y2–8x–6y+9 = 0 and x2+y2–8x–6y–11 = 0
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