Maths-

General

Easy

Question

# D and E are points on the base BC of such that BD = CE. If AD = AE, prove that.

Hint:

### prove the given condition by using similarity of triangles

## The correct answer is: Hence proved

### In ACD and ABE

AD = AE (given)

BD = EC (given)

Now adding DE on both side to above conditions ,

BD + DE = DE + EC

BE = CD

∠ADC = ∠AEB (as AD = AE)

By SAS rule , ABE ≅ ACD

Then , by congruence ∠ABE = ∠ACD

Hence proved

By SAS rule , ABE ≅ ACD

Then , by congruence ∠ABE = ∠ACD

Hence proved

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