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If tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi sin space theta right parenthesis comma 0 less than theta less than fraction numerator 3 pi over denominator 4 end fraction then sin space open parentheses theta plus pi over 4 close parentheses equals

Maths-General

  1. fraction numerator 1 over denominator 2 square root of 2 end fraction
  2. negative fraction numerator 1 over denominator 2 square root of 2 end fraction
  3. negative fraction numerator 1 over denominator square root of 2 end fraction
  4. fraction numerator 1 over denominator square root of 2 end fraction

    Answer:The correct answer is: fraction numerator 1 over denominator 2 square root of 2 end fraction

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    If tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction and tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root then alpha plus beta =

    If tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction and tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root then alpha plus beta =

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    General
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    open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses =

    open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses =

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    General
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    The minimum value bold m bold space 2 cos space theta plus fraction numerator 1 over denominator sin invisible function application theta end fraction plus square root of 2 tan space theta space text  in  end text open parentheses 0 comma pi over 2 close parentheses is

    The minimum value bold m bold space 2 cos space theta plus fraction numerator 1 over denominator sin invisible function application theta end fraction plus square root of 2 tan space theta space text  in  end text open parentheses 0 comma pi over 2 close parentheses is

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    General
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    In the adjoining figure, stack left floor a with _ below equals left floor b and left floor c equals left floor d comma then left floor b plus left floor c equals

    In the adjoining figure, stack left floor a with _ below equals left floor b and left floor c equals left floor d comma then left floor b plus left floor c equals

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    General
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    In the figure, a equals 4 x to the power of ring operator end exponent and b equals left parenthesis 2.5 x plus 24 right parenthesis to the power of ring operator end exponent comma then the value of x =

    In the figure, a equals 4 x to the power of ring operator end exponent and b equals left parenthesis 2.5 x plus 24 right parenthesis to the power of ring operator end exponent comma then the value of x =

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    General
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    In the figure A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent then ACD=

    In the figure A equals 30 to the power of ring operator end exponent & E B equals 50 to the power of ring operator end exponent then ACD=

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    General
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    In the following figure, the value of x =

    In the following figure, the value of x =

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    General
    maths-

    Using information given in the following figure, the value of x and y is

    Using information given in the following figure, the value of x and y is

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    General
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    In figure, the sides QP and RQ of triangle P Q R are produced to points S and T respectively. If stack S P R with _ below equals 135 to the power of ring operator end exponent and open floor P Q T equals 110 to the power of ring operator end exponent close then stack P R Q with _ below equals

    In figure, the sides QP and RQ of triangle P Q R are produced to points S and T respectively. If stack S P R with _ below equals 135 to the power of ring operator end exponent and open floor P Q T equals 110 to the power of ring operator end exponent close then stack P R Q with _ below equals

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    General
    maths-

    In the given figure, if P Q R equals 70 to the power of ring operator end exponent then ∣ A B C equals

    In the given figure, if P Q R equals 70 to the power of ring operator end exponent then ∣ A B C equals

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    General
    maths-

    From the given figure, the value of ‘a’ is

    From the given figure, the value of ‘a’ is

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    General
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    In the following figure, AB is parallel to CD , then the value of x in degrees is

    In the following figure, AB is parallel to CD , then the value of x in degrees is

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    General
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    If AB=AC and A C D equals 115 to the power of ring operator end exponent then stack B with _ below A C equals

    If AB=AC and A C D equals 115 to the power of ring operator end exponent then stack B with _ below A C equals

    maths-General
    General
    maths-

    In the given figure, l parallel to m then the value of x =

    In the given figure, l parallel to m then the value of x =

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    General
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    In the given figure, stack A B with bar on top is parallel to CD, then x =

    In the given figure, stack A B with bar on top is parallel to CD, then x =

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