Maths-
General
Easy

Question

If in a triangle ABC; AD, BE and CF are the altitudes and R is the circum-radius, then the radius of the circle DEF is -

  1. R/2    
  2. 2R    
  3. R    
  4. None of these    

hintHint:

 

The correct answer is: R/2


    Given :-In a triangle ABC; AD, BE and CF are the altitudes and R is the circum-radius, then we have to find the radius of the circle DEF.

    In pedal DEF
    EF=acosA
    DE=ccosC
    DF=bcosB

    If circum-radius of  DEF isR subscript 1
T h e n comma space R subscript 1 equals fraction numerator left parenthesis a cos A right parenthesis left parenthesis b cos B right parenthesis left parenthesis c cos C right parenthesis space ​ space space over denominator 4 cross times begin display style 1 half end style D F. D E space sin left parenthesis angle E D F right parenthesis end fraction
H e r e space angle E D F equals 180 minus 2 A
equals fraction numerator a b c space cos A space cos B space cos C over denominator 4 cross times 1 half cross times b space cos B. c space cos C. sin left parenthesis 180 minus 2 A right parenthesis end fraction
equals fraction numerator a cos A over denominator 2 sin 2 A end fraction
S u b s t i t u t e space f o r space space a equals 2 R sin A
equals fraction numerator 2 R sin A cos A over denominator 4 sin A space cos A end fraction
R subscript 1 equals R over 2

    Therefore, the radius of the circle DEF is R/2.

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