Maths-
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Easy

Question

If the function fraction numerator c o s invisible function application x plus K s i n invisible function application x over denominator 2 c o s invisible function application x plus 3 s i n invisible function application x end fraction is decreasing in its domain then K E

  1. open parentheses fraction numerator 3 over denominator 2 end fraction comma infinity close parentheses    
  2. open parentheses 0 comma fraction numerator 3 over denominator 2 end fraction close parentheses    
  3. open parentheses negative infinity comma fraction numerator 3 over denominator 2 end fraction close parentheses    
  4. left parenthesis negative infinity comma 0 right parenthesis    

The correct answer is: open parentheses negative infinity comma fraction numerator 3 over denominator 2 end fraction close parentheses

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