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Question

In given figure stack A B with rightwards arrow on top equals stack A C with bar on top and stack B C with bar on top equals stack C D with bar on top comma if B A C equals 80 to the power of ring operator end exponent blankthen find ∣ C D B

  1. 15 to the power of 0 end exponent    
  2. 25 to the power of 0 end exponent    
  3. 20 to the power of 0 end exponent    
  4. 30 to the power of 0 end exponent    

The correct answer is: 30 to the power of 0 end exponent

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In the diagram, if triangle A B C and capital delta P Q R are Equilateral then find text C  end text X Y

In the diagram, if triangle A B C and capital delta P Q R are Equilateral then find text C  end text X Y

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if a to the power of 2 end exponent plus b to the power of 2 end exponent plus c to the power of 2 end exponent equals a b plus b c plus c a then the triangle is

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A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

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A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

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Maximum acceleration will be represented by C D part of the graph
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The position of a particle at any instant t is given by x equals acos omega t. The speed-time graph of the particle is

therefore blank x equals acos omega t
therefore v equals fraction numerator d x over denominator d t end fraction equals negative a omega sin invisible function application omega t
The instantaneous speed is given by modulus of instantaneous velocity.
therefore blankspeedequals open vertical bar u close vertical bar equals open vertical bar negative a omega sin invisible function application omega t close vertical bar
Hence, [c] is correct.

The position of a particle at any instant t is given by x equals acos omega t. The speed-time graph of the particle is

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therefore blank x equals acos omega t
therefore v equals fraction numerator d x over denominator d t end fraction equals negative a omega sin invisible function application omega t
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Hence, [c] is correct.
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The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 blank s e c are respectively

Displacement = Summation of all the area with sign
equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses equals open parentheses 2 cross times 4 close parentheses plus open parentheses negative 2 cross times 2 close parentheses plus open parentheses 2 cross times 2 close parentheses

therefore D i s p l a c e m e n t equals 8 blank m
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equals open vertical bar A subscript 1 end subscript close vertical bar plus open vertical bar negative A subscript 2 end subscript close vertical bar plus open vertical bar A subscript 3 end subscript close vertical bar equals open vertical bar 8 close vertical bar plus open vertical bar negative 4 close vertical bar plus open vertical bar 4 close vertical bar equals 8 plus 4 plus 4
therefore D i s t a n c e equals 16 blank m

The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 blank s e c are respectively

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equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses equals open parentheses 2 cross times 4 close parentheses plus open parentheses negative 2 cross times 2 close parentheses plus open parentheses 2 cross times 2 close parentheses

therefore D i s p l a c e m e n t equals 8 blank m
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therefore D i s t a n c e equals 16 blank m
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From the figure

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From the figure
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