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The equation of the circle passing through pole and centre at (4,0) is

Maths-General

  1. r equals 8 C o s space theta    
  2. r equals 4 C o s space theta    
  3. r equals 8 S i n space theta    
  4. r equals 4 S i n space theta    

    Answer:The correct answer is: r equals 8 C o s space theta

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    The equation of the directrix of the conic r C o s to the power of 2 end exponent invisible function application open parentheses fraction numerator theta over denominator 2 end fraction close parentheses equals 5 is

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    The castesian equation of r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p is

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    The cartesian equation of r squared c o s space 2 theta equals a squared is

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    ax2 + bx + c = 0 has real and distinct roots null. Further a > 0, b < 0 and c < 0, then –

    ax2 + bx + c = 0 has real and distinct roots null. Further a > 0, b < 0 and c < 0, then –

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    A small source of sound moves on a circle as shown in the figure and an observer is standing on O. Let n subscript 1 end subscript comma n subscript 2 end subscript and n subscript 3 end subscript be the frequencies heard when the source is at A comma blank B blankand C respectively. Then

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    If alpha not equal to beta comma alpha 2 equals 5 alpha minus 3 comma beta 2 times equals 5 beta minus 3 commathen the equation whose roots are alpha divided by beta straight & beta divided by alpha

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    If x, y, z are integers and x greater or equal than 0, y greater or equal than 1, z greater or equal than 2, x + y + z = 15, then the number of values of the ordered triplet (x, y, z) is -

    Let y = p + 1 and z = q + 2.
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    therefore The reqd. number of values of (x, y, z) and hence of (x, p, q)
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    = Coeff. of x12 in (x0 + x1 + x2 + ……)3
    = Coeff. of x12 in (1 – x)–3
    = Coeff. of x12 in [2C0 + 3C1 x + 4C2 x2 + ….]
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    Let y = p + 1 and z = q + 2.
    Then x greater or equal than 0, p greater or equal than 0, q greater or equal than 0 and x + y + z = 15
    rightwards double arrow x + p + q = 12
    therefore The reqd. number of values of (x, y, z) and hence of (x, p, q)
    = No. of non-negative integral solutions of x + p + q= 12
    = Coeff. of x12 in (x0 + x1 + x2 + ……)3
    = Coeff. of x12 in (1 – x)–3
    = Coeff. of x12 in [2C0 + 3C1 x + 4C2 x2 + ….]
    = 14C12 = fraction numerator 14 factorial over denominator 2 factorial 12 factorial end fraction = fraction numerator 14 cross times 13 over denominator 2 end fraction = 91.
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    The polar equation of the straight line parallel to the initial line and at a distance of 4 units above the initial line is

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