The polar equation of x^(3)+y^(3)=3 axy is -Turito

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Maths-

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Easy

Question

The polar equation of $x to the power of 3 end exponent plus y to the power of 3 end exponent equals 3$ axy is

$r ({C o s}^{3} θ + {S i n}^{3} θ) = 3 a C o s θ S i n θ$
$r ({C o s}^{3} θ + {S i n}^{3} θ) = a C o s 2 θ$
$r ({C o s}^{3} θ - {S i n}^{3} θ) = 3 a C o s θ S i n θ$
$r ({C o s}^{3} θ - {S i n}^{3} θ) = a C o s 2 θ$

The correct answer is: $r open parentheses C o s cubed space theta plus S i n cubed space theta close parentheses equals 3 a C o s space theta S i n space theta$

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