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# The polar equation of axy is

## The correct answer is:

### Related Questions to study

maths-

### If x, y, z are integers and x 0, y 1, z 2, x + y + z = 15, then the number of values of the ordered triplet (x, y, z) is -

Let y = p + 1 and z = q + 2.

Then x 0, p 0, q 0 and x + y + z = 15

x + p + q = 12

The reqd. number of values of (x, y, z) and hence of (x, p, q)

= No. of non-negative integral solutions of x + p + q= 12

= Coeff. of x

= Coeff. of x

= Coeff. of x

=

Then x 0, p 0, q 0 and x + y + z = 15

x + p + q = 12

The reqd. number of values of (x, y, z) and hence of (x, p, q)

= No. of non-negative integral solutions of x + p + q= 12

= Coeff. of x

^{12}in (x^{0}+ x^{1}+ x^{2}+ ……)^{3}= Coeff. of x

^{12}in (1 – x)^{–3}= Coeff. of x

^{12}in [^{2}C_{0}+^{3}C_{1}x +^{4}C_{2}x^{2}+ ….]=

^{14}C_{12}= = = 91.### If x, y, z are integers and x 0, y 1, z 2, x + y + z = 15, then the number of values of the ordered triplet (x, y, z) is -

maths-General

Let y = p + 1 and z = q + 2.

Then x 0, p 0, q 0 and x + y + z = 15

x + p + q = 12

The reqd. number of values of (x, y, z) and hence of (x, p, q)

= No. of non-negative integral solutions of x + p + q= 12

= Coeff. of x

= Coeff. of x

= Coeff. of x

=

Then x 0, p 0, q 0 and x + y + z = 15

x + p + q = 12

The reqd. number of values of (x, y, z) and hence of (x, p, q)

= No. of non-negative integral solutions of x + p + q= 12

= Coeff. of x

^{12}in (x^{0}+ x^{1}+ x^{2}+ ……)^{3}= Coeff. of x

^{12}in (1 – x)^{–3}= Coeff. of x

^{12}in [^{2}C_{0}+^{3}C_{1}x +^{4}C_{2}x^{2}+ ….]=

^{14}C_{12}= = = 91.Maths-

### If then the equation whose roots are

### If then the equation whose roots are

Maths-General

Maths-

### Let p, q {1, 2, 3, 4}. Then number of equation of the form px^{2} + qx + 1 = 0, having real roots, is

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given p, q {1, 2, 3, 4}, the equation given is : px

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given p, q {1, 2, 3, 4}, the equation given is : px

^{2}+ qx + 1 = 0Now we know that for real roots, the discriminant is always greater than or equal to $0, so we have:$

D=b

$q−4p≥0⇒q≥4p$

Now the set includes 4 terms, putting each, we get:

^{2}-4ac, applying this, we get:$q−4p≥0⇒q≥4p$

Now the set includes 4 terms, putting each, we get:

For $p=1,q≥4$

$q=2,3,4$

For $p=2,q≥8$

$q=3,4$

For $p=3q≥12$

$q=4$

For $p=4,q≥16$

$q=4$

So here we can see that total 7 seven solutions are possible so $7$ equations can be formed.

### Let p, q {1, 2, 3, 4}. Then number of equation of the form px^{2} + qx + 1 = 0, having real roots, is

Maths-General

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given p, q {1, 2, 3, 4}, the equation given is : px

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given p, q {1, 2, 3, 4}, the equation given is : px

^{2}+ qx + 1 = 0Now we know that for real roots, the discriminant is always greater than or equal to $0, so we have:$

D=b

$q−4p≥0⇒q≥4p$

Now the set includes 4 terms, putting each, we get:

^{2}-4ac, applying this, we get:$q−4p≥0⇒q≥4p$

Now the set includes 4 terms, putting each, we get:

For $p=1,q≥4$

$q=2,3,4$

For $p=2,q≥8$

$q=3,4$

For $p=3q≥12$

$q=4$

For $p=4,q≥16$

$q=4$

So here we can see that total 7 seven solutions are possible so $7$ equations can be formed.

Maths-

### ax^{2} + bx + c = 0 has real and distinct roots null. Further a > 0, b < 0 and c < 0, then –

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given a > 0, b < 0 and c < 0, the equation is ax

Let the roots be α and β, where β>α, then:

α + β = -b/a $>0$ as $a>0,b<0$.

αβ = c/a as $a>0,c<0$.

Now that the roots are of opposite signs, so β > 0 and α < 0.

So: $α∣β$ as α$β>0$.

So therefore: 0 < ∣α∣ < β

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given a > 0, b < 0 and c < 0, the equation is ax

^{2}+ bx + c = 0.Let the roots be α and β, where β>α, then:

α + β = -b/a $>0$ as $a>0,b<0$.

αβ = c/a as $a>0,c<0$.

Now that the roots are of opposite signs, so β > 0 and α < 0.

So: $α∣β$ as α$β>0$.

So therefore: 0 < ∣α∣ < β

### ax^{2} + bx + c = 0 has real and distinct roots null. Further a > 0, b < 0 and c < 0, then –

Maths-General

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given a > 0, b < 0 and c < 0, the equation is ax

Let the roots be α and β, where β>α, then:

α + β = -b/a $>0$ as $a>0,b<0$.

αβ = c/a as $a>0,c<0$.

Now that the roots are of opposite signs, so β > 0 and α < 0.

So: $α∣β$ as α$β>0$.

So therefore: 0 < ∣α∣ < β

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given a > 0, b < 0 and c < 0, the equation is ax

^{2}+ bx + c = 0.Let the roots be α and β, where β>α, then:

α + β = -b/a $>0$ as $a>0,b<0$.

αβ = c/a as $a>0,c<0$.

Now that the roots are of opposite signs, so β > 0 and α < 0.

So: $α∣β$ as α$β>0$.

So therefore: 0 < ∣α∣ < β

Maths-

### The cartesian equation of is

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given the equation as .

Now we know that:

.

So applying this, we get:

Now lets substitute x=$rcosθ andy=rsinθ, we get:$

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given the equation as .

Now we know that:

.

So applying this, we get:

Now lets substitute x=$rcosθ andy=rsinθ, we get:$

### The cartesian equation of is

Maths-General

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given the equation as .

Now we know that:

.

So applying this, we get:

Now lets substitute x=$rcosθ andy=rsinθ, we get:$

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given the equation as .

Now we know that:

.

So applying this, we get:

Now lets substitute x=$rcosθ andy=rsinθ, we get:$

Maths-

### The castesian equation of is

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given the equation as .

Now we know that:

.

So applying this, we get:

Now lets substitute x=$rcosθ andy=rsinθ, we get:$

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given the equation as .

Now we know that:

.

So applying this, we get:

Now lets substitute x=$rcosθ andy=rsinθ, we get:$

### The castesian equation of is

Maths-General

ax² + bx + c = 0

where a, b, and c are constant terms and x is the unknown variable.

Now we have given the equation as .

Now we know that:

.

So applying this, we get:

Now lets substitute x=$rcosθ andy=rsinθ, we get:$

maths-

### The equation of the directrix of the conic whose length of the latusrectum is 5 and eccenticity is 1/2 is

### The equation of the directrix of the conic whose length of the latusrectum is 5 and eccenticity is 1/2 is

maths-General

maths-

### The equation of the directrix of the conic is

### The equation of the directrix of the conic is

maths-General

maths-

### The equation of the circle touching the initial line at pole and radius 2 is

### The equation of the circle touching the initial line at pole and radius 2 is

maths-General

maths-

### The equation of the circle passing through pole and centre at (4,0) is

### The equation of the circle passing through pole and centre at (4,0) is

maths-General

Maths-

### The polar equation of the circle with pole as centre and radius 3 is

### The polar equation of the circle with pole as centre and radius 3 is

Maths-General

maths-

### (Area of GPL) to (Area of ALD) is equal to

### (Area of GPL) to (Area of ALD) is equal to

maths-General

physics-

### A small source of sound moves on a circle as shown in the figure and an observer is standing on Let and be the frequencies heard when the source is at and respectively. Then

At point source is moving away from observer so apparent frequency (actual frequency) At point source is coming towards observer so apparent frequency and point source is moving perpendicular to observer so

Hence

Hence

### A small source of sound moves on a circle as shown in the figure and an observer is standing on Let and be the frequencies heard when the source is at and respectively. Then

physics-General

At point source is moving away from observer so apparent frequency (actual frequency) At point source is coming towards observer so apparent frequency and point source is moving perpendicular to observer so

Hence

Hence

Maths-

### In a triangle ABC, if a : b : c = 7 : 8 : 9, then cos A : cos B equals to

### In a triangle ABC, if a : b : c = 7 : 8 : 9, then cos A : cos B equals to

Maths-General

physics-

### Which of the following curves represents correctly the oscillation given by

Given equation

At

This is case with curve marked

At

This is case with curve marked

### Which of the following curves represents correctly the oscillation given by

physics-General

Given equation

At

This is case with curve marked

At

This is case with curve marked