Maths-
General
Easy

Question

# Let p, q  {1, 2, 3, 4}. Then number of equation of the form px2 + qx + 1 = 0, having real roots, is

Hint:

## The correct answer is: 7

### A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:ax² + bx + c = 0where a, b, and c are constant terms and x is the unknown variable.Now we have given  p, q  {1, 2, 3, 4}, the equation given is : px2 + qx + 1 = 0Now we know that for real roots, the discriminant is always greater than or equal to  D=b2-4ac, applying this, we get:Now the set includes 4 terms, putting each, we get: For    For    For    For  So here we can see that total 7 seven solutions are possible so  equations can be formed.

Here we used the concept of quadratic equations and solved the problem. We also understood the concept of discriminant and used it in the solution to find the intervals. Therefore, total 7 seven solutions are possible so 7 equations can be formed.