Maths-
The equation of the circle touching the initial line at pole and radius 2 is
Maths-General
Answer:The correct answer is: 
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The equation of the circle passing through pole and centre at (4,0) is
The equation of the circle passing through pole and centre at (4,0) is
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The polar equation of the circle with pole as centre and radius 3 is
The polar equation of the circle with pole as centre and radius 3 is
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The equation of the directrix of the conic
is
The equation of the directrix of the conic
is
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The equation of the directrix of the conic whose length of the latusrectum is 5 and eccenticity is 1/2 is
The equation of the directrix of the conic whose length of the latusrectum is 5 and eccenticity is 1/2 is
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The castesian equation of
is
The castesian equation of
is
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The cartesian equation of
is
The cartesian equation of
is
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(Area of
GPL) to (Area of
ALD) is equal to
(Area of
GPL) to (Area of
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ax2 + bx + c = 0 has real and distinct roots null. Further a > 0, b < 0 and c < 0, then –
ax2 + bx + c = 0 has real and distinct roots null. Further a > 0, b < 0 and c < 0, then –
maths-General
maths-
Let p, q
{1, 2, 3, 4}. Then number of equation of the form px2 + qx + 1 = 0, having real roots, is
Let p, q
{1, 2, 3, 4}. Then number of equation of the form px2 + qx + 1 = 0, having real roots, is
maths-General
maths-
If
then the equation whose roots are 
If
then the equation whose roots are 
maths-General
physics-
A small source of sound moves on a circle as shown in the figure and an observer is standing on
Let
and
be the frequencies heard when the source is at
and
respectively. Then

At point
source is moving away from observer so apparent frequency
(actual frequency) At point
source is coming towards observer so apparent frequency
and point
source is moving perpendicular to observer so 
Hence
Hence
A small source of sound moves on a circle as shown in the figure and an observer is standing on
Let
and
be the frequencies heard when the source is at
and
respectively. Then

physics-General
At point
source is moving away from observer so apparent frequency
(actual frequency) At point
source is coming towards observer so apparent frequency
and point
source is moving perpendicular to observer so 
Hence
Hence
maths-
If x, y, z are integers and x
0, y
1, z
2, x + y + z = 15, then the number of values of the ordered triplet (x, y, z) is -
Let y = p + 1 and z = q + 2.
Then x
0, p
0, q
0 and x + y + z = 15
x + p + q = 12
The reqd. number of values of (x, y, z) and hence of (x, p, q)
= No. of non-negative integral solutions of x + p + q= 12
= Coeff. of x12 in (x0 + x1 + x2 + ……)3
= Coeff. of x12 in (1 – x)–3
= Coeff. of x12 in [2C0 + 3C1 x + 4C2 x2 + ….]
= 14C12 =
=
= 91.
Then x
= No. of non-negative integral solutions of x + p + q= 12
= Coeff. of x12 in (x0 + x1 + x2 + ……)3
= Coeff. of x12 in (1 – x)–3
= Coeff. of x12 in [2C0 + 3C1 x + 4C2 x2 + ….]
= 14C12 =
If x, y, z are integers and x
0, y
1, z
2, x + y + z = 15, then the number of values of the ordered triplet (x, y, z) is -
maths-General
Let y = p + 1 and z = q + 2.
Then x
0, p
0, q
0 and x + y + z = 15
x + p + q = 12
The reqd. number of values of (x, y, z) and hence of (x, p, q)
= No. of non-negative integral solutions of x + p + q= 12
= Coeff. of x12 in (x0 + x1 + x2 + ……)3
= Coeff. of x12 in (1 – x)–3
= Coeff. of x12 in [2C0 + 3C1 x + 4C2 x2 + ….]
= 14C12 =
=
= 91.
Then x
= No. of non-negative integral solutions of x + p + q= 12
= Coeff. of x12 in (x0 + x1 + x2 + ……)3
= Coeff. of x12 in (1 – x)–3
= Coeff. of x12 in [2C0 + 3C1 x + 4C2 x2 + ….]
= 14C12 =
maths-
The polar equation of
axy is
The polar equation of
axy is
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The polar equation of the straight line parallel to the initial line and at a distance of 4 units above the initial line is
The polar equation of the straight line parallel to the initial line and at a distance of 4 units above the initial line is
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maths-
The polar equation of the straight line with intercepts 'a' and 'b' on the rays
and
respectively is
The polar equation of the straight line with intercepts 'a' and 'b' on the rays
and
respectively is
maths-General