Mathematics
Grade-4-
Easy
Question
The pair of fractions among the following that are not equivalent is
Hint:
To find out whether the pair of fraction is equivalent we have to do cross multiplication. For this we have to multiply the numerator of first fraction and the denominator of second, and numerator of second fraction to the denominator of first. If the products are equal the fractions are equivalent and vice versa.
The correct answer is:
a. 
and 
2
18 123
= 36 = 36
As the cross multiplication of both fractions are equal. So its an equivalent fraction.
b. 
and 
4
= 200 = 200
As the cross multiplication of both fraction are equal. So its an equivalent fraction.
c. 
= 3 = 4
as the cross multiplication of both fractions are not equal. So its not an equivalent fraction.
d. 
14
= 84 = 84
as the cross multiplication of both fractions are equal. So its an equivalent fraction.
Therefore the pair of fraction which is not an equivalent fraction is 
.
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A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is:
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Let the probability of getting balls be x.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
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but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
Then the probability of getting blue ball = 2x
As we know the sum of probability of all the possible outcomes is 1.
So, 2x + x = 1
Let total number of probability be P.
The probability of getting red balls =
but as derived probability of getting red ball = x =
So,
total number of outcome i.e. total no. balls is 15
so, no. blue balls = 15 - 5 =10.
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From a bag of 2 red, 3 blue and 2 black balls. A ball is picked out at random. The probability to get red ball is_______
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Possibility=
So, probability of getting red ball is
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No. of possible outcome ( no. of red balls)= 2
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Total no. of total outcome = 2+3+2=7
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So, probability of getting red ball is.
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If the sum is 10 when two fair dice are tossed then the probability is__________.
Total number outcomes = 36
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
If the sum is 10 when two fair dice are tossed then the probability is__________.
MathematicsGrade-4-
Total number outcomes = 36
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
[ (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)]
Possible outcomes = 3
Possibility =
So, if the sum is 10 when two fair dice are tossed then the probability is
Mathematics
A coin has ___.
A coin has one head and one tail.
A coin has ___.
MathematicsGrade-4-
A coin has one head and one tail.
Mathematics
The probability of picking an alphabet from consonants is
Here, we have to find the probability of picking an alphabet from consonant of the English alphabet at random.
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
The probability of picking an alphabet from consonants is
MathematicsGrade-4-
Here, we have to find the probability of picking an alphabet from consonant of the English alphabet at random.
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
Total number of outcomes = Number of consonants = 21
Therefore, probability of picking an alphabet from consonant = 1/21
Hence, the correct option is (c).
