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Question

If f : R →R; f(x) = sin x + x, then the value of not stretchy integral subscript 0 end subscript superscript pi end superscript blank (f-1 (x)) dx, is equal to

  1. fraction numerator pi to the power of 2 end exponent over denominator 2 end fraction minus 2    
  2. p2    
  3. fraction numerator pi to the power of 2 end exponent over denominator 2 end fraction plus 2    
  4. None of these    

hintHint:

The calculation of an integral is known as integration. Numerous important quantities in mathematics, such as areas, volumes, displacement, etc., can be found using integrals. Apart from differentiation, one of the two main calculus topics in mathematics is integration (which measure the rate of change of any function with respect to its variables). Here we have to find not stretchy integral subscript 0 end subscript superscript pi end superscript blank (f-1 (x)) dx.

The correct answer is: fraction numerator pi to the power of 2 end exponent over denominator 2 end fraction minus 2


    The summing of discrete data is indicated by the integration. To determine the functions that will characterise the area, displacement, and volume that result from a combination of small data that cannot be measured separately, integrals are calculated.
    We are aware that differentiation is the process of discovering a function's derivative and integration is the process of discovering a function's antiderivative. Thus, both processes are the antithesis of one another. Therefore, we can say that differentiation is the process of differentiation and integration is the reverse.
    Here we have given the function f : R →R; f(x) = sin x + x
    N o w space m a t h e m a t i c a l l y colon
straight pi squared equals integral subscript 0 superscript straight pi straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis dx space plus integral subscript 0 superscript straight pi straight f left parenthesis straight x right parenthesis dx
integral subscript 0 superscript straight pi straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis dx equals straight pi squared minus integral subscript 0 superscript straight pi straight f left parenthesis straight x right parenthesis dx
integral subscript 0 superscript straight pi straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis dx equals straight pi squared minus integral subscript 0 superscript straight pi left parenthesis sinx plus straight x right parenthesis dx
integral subscript 0 superscript straight pi straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis dx equals straight pi squared minus open square brackets negative cosx plus straight x squared over 2 close square brackets subscript 0 superscript straight pi
integral subscript 0 superscript straight pi straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis dx equals straight pi squared minus open square brackets negative left parenthesis negative 1 minus 1 right parenthesis plus straight pi squared over 2 close square brackets
integral subscript 0 superscript straight pi straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis dx equals straight pi squared over 2 minus 2

    Here we used the concept of integration and the inverse functions to solve the question. Finding an antiderivative of a function is the procedure known as integration. The process of adding the slices to complete it is comparable. The process of integration is the opposite of that of differentiation. So the final answer is straight pi squared over 2 minus 2.

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