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Question

The number of distinct real roots of $open vertical bar table attributes columnalign center center center columnspacing 1em end attributes row cell sin invisible function application x end cell cell cos invisible function application x end cell cell cos invisible function application x end cell row cell cos invisible function application x end cell cell sin invisible function application x end cell cell cos invisible function application x end cell row cell cos invisible function application x end cell cell cos invisible function application x end cell cell sin invisible function application x end cell end table close vertical bar equals 0$ in the interval $negative pi over 4 less or equal than x less or equal than pi over 4$ is

0
2
1
3

The correct answer is: 1

Related Questions to study

If $0 less or equal than x less than 2 pi$ , then the number of real values of x, which satisfy the equation $cos invisible function application x plus cos invisible function application 2 x plus cos invisible function application 3 x plus cos invisible function application 4 x equals 0$ is :

If $0 less or equal than x less than 2 pi$ , then the number of real values of x, which satisfy the equation $cos invisible function application x plus cos invisible function application 2 x plus cos invisible function application 3 x plus cos invisible function application 4 x equals 0$ is :

The number of solutions of the equation $cos squared invisible function application open parentheses x plus pi over 6 close parentheses plus cos squared invisible function application x minus 2 cos invisible function application open parentheses x plus pi over 6 close parentheses cos invisible function application open parentheses pi over 6 close parentheses equals sin squared invisible function application pi over 6$ in the interval $left parenthesis negative pi divided by 2 comma pi divided by 2 right parenthesis$ is

The number of solutions of the equation $cos squared invisible function application open parentheses x plus pi over 6 close parentheses plus cos squared invisible function application x minus 2 cos invisible function application open parentheses x plus pi over 6 close parentheses cos invisible function application open parentheses pi over 6 close parentheses equals sin squared invisible function application pi over 6$ in the interval $left parenthesis negative pi divided by 2 comma pi divided by 2 right parenthesis$ is

The possible values of $theta element of left parenthesis 0 comma pi right parenthesis$ such that $sin invisible function application theta plus sin invisible function application 4 theta plus sin invisible function application 7 theta equals 0$ are :

The possible values of $theta element of left parenthesis 0 comma pi right parenthesis$ such that $sin invisible function application theta plus sin invisible function application 4 theta plus sin invisible function application 7 theta equals 0$ are :

parallel

The number of values of x in the interval [0, 3 $straight pi$ ] satisfying the equation , $2 sin squared invisible function application x plus 5 sin invisible function application x minus 3 equals 0$ is

The number of values of x in the interval [0, 3 $straight pi$ ] satisfying the equation , $2 sin squared invisible function application x plus 5 sin invisible function application x minus 3 equals 0$ is

The number of solutions of tan x + sec x = 2 cos x in [0, 2 $straight pi$ ], is

The number of solutions of tan x + sec x = 2 cos x in [0, 2 $straight pi$ ], is

Over $left square bracket negative pi comma pi right square bracket$ the solution of $2 sin squared invisible function application open parentheses x plus pi over 4 close parentheses plus square root of 3 cos invisible function application 2 x greater or equal than 0$ is

Over $left square bracket negative pi comma pi right square bracket$ the solution of $2 sin squared invisible function application open parentheses x plus pi over 4 close parentheses plus square root of 3 cos invisible function application 2 x greater or equal than 0$ is

parallel

Solution to inequality cos 2x + 5 cos x + 3 ≥ 0 over $left square bracket negative pi comma pi right square bracket$ is

Solution to inequality cos 2x + 5 cos x + 3 ≥ 0 over $left square bracket negative pi comma pi right square bracket$ is

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The general solution of the trigonometric equation tan x + tan 2x + tan 3x = tan x · tan 2x tan 3x is
where n $element of$ I

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where n $element of$ I

parallel

The sum of all the solution of cotθ= sin 2θ(θ ≠ n $straight pi$ , n integer), 0 , $less or equal than theta less or equal than pi$ is

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$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 1 plus x right parenthesis to the power of 1 fifth end exponent minus left parenthesis 1 minus x right parenthesis to the power of 1 half end exponent over denominator x end fraction$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin space open parentheses pi cos squared space x close parentheses over denominator x squared end fraction$

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parallel

$L subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of x minus e cubed over denominator x not stretchy rightwards arrow 0 end fraction$

$L subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of x minus e cubed over denominator x not stretchy rightwards arrow 0 end fraction$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of 3 x end exponent minus e cubed over denominator x end fraction$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of 3 x end exponent minus e cubed over denominator x end fraction$

$Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application fraction numerator e to the power of 7 x end exponent minus 1 over denominator 7 x end fraction$

$Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application fraction numerator e to the power of 7 x end exponent minus 1 over denominator 7 x end fraction$

parallel

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