The range of the function $f left parenthesis x right parenthesis equals fraction numerator 2 plus x over denominator 2 minus x end fraction comma x not equal to 2 text end text$ is-

Hence, the function f(x+y)=f(x)+f(y) is symmetric about the origin.

The minimum value of $f left parenthesis x right parenthesis equals vertical line 3 minus x vertical line plus vertical line 2 plus x vertical line plus vertical line 5 minus x vertical line$ is

$f colon left square bracket negative 1 , 1 right square bracket rightwards arrow left square bracket negative 1 , 2 right square bracket comma f left parenthesis x right parenthesis equals x plus vertical line x vertical line comma$ is -

Hence, the given function is many one and onto.

$f colon left square bracket negative 1 , 1 right square bracket rightwards arrow left square bracket negative 1 , 2 right square bracket comma f left parenthesis x right parenthesis equals x plus vertical line x vertical line comma$ is -

Hence, the given function is many one and onto.

If f(x) is a polynomial function satisfying the condition f(x). f(1/x) = f(x) + f(1/x) and f(2) = 9 then -

Fill in the blank with the appropriate transition.
The movie managed to fetch decent collections ______ all the negative reviews it received.

GeneralGeneral

If R be a relation '<' from A = {1, 2, 3, 4} to B = {1, 3, 5} i.e. (a, b) $element of$ R iff a < b, then $R O R to the power of negative 1 end exponent text end text$ is $text-end text$

Values of $R O R to the power of negative 1 end exponent text end text$ are {(3, 3), (3, 5), (5, 3), (5, 5)}

If R be a relation '<' from A = {1, 2, 3, 4} to B = {1, 3, 5} i.e. (a, b) $element of$ R iff a < b, then $R O R to the power of negative 1 end exponent text end text$ is $text-end text$

Values of $R O R to the power of negative 1 end exponent text end text$ are {(3, 3), (3, 5), (5, 3), (5, 5)}

Which one of the following relations on R is equivalence relation

Let R = {(x, y) : x, y $element of$ A, x + y = 5} where A = {1, 2, 3, 4, 5} then

Hence, the given relation is not reflexive, symmetric and not transitive

Let R = {(x, y) : x, y $element of$ A, x + y = 5} where A = {1, 2, 3, 4, 5} then

Hence, the given relation is not reflexive, symmetric and not transitive

Let $R subscript 1 end subscript text , end text$ be a relation defined by $R subscript 1 end subscript equals left curly bracket left parenthesis a comma b right parenthesis ∣ a greater or equal than b semicolon a comma b element of R right curly bracket text . end text$ Then R is

Hence, the given relation is Reflexive, transitive but not symmetric.

Let $R subscript 1 end subscript text , end text$ be a relation defined by $R subscript 1 end subscript equals left curly bracket left parenthesis a comma b right parenthesis ∣ a greater or equal than b semicolon a comma b element of R right curly bracket text . end text$ Then R is

Hence, the given relation is Reflexive, transitive but not symmetric.

The relation R defined in N as aRb $left right double arrow$ b is divisible by a is

Hence, the given relations is reflexive but not symmetric.

The relation R defined in N as aRb $left right double arrow$ b is divisible by a is

Hence, the given relations is reflexive but not symmetric.

Electric power =

n equal resistors are first connected in series and then in parallel. The ratio of the equivalent resistance in the two cases is

The equivalent resistance of the network shown in the adjoining figure between the points A and B is

A current of 4.8 A is flowing in a conductor. The number of electrons passing through any cross-section per second is

Equivalent resistance between points P and Q in the adjoining figure is