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Maths-

General

Easy

Question

The three s ides of $triangle A B C$ are extended as shown so that $B D equals fraction numerator 1 over denominator 2 end fraction A B comma C E equals fraction numerator 1 over denominator 2 end fraction B C$ and $A F equals fraction numerator 1 over denominator 2 end fraction C A$ Find the ratio of the area of $capital delta D E F$ to that of $triangle A B C.$

14 : 5
10 : 3
13 : 4
7 : 2

The correct answer is: 14 : 5

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