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Physics-

General

Easy

Question

A particle is acted upon by a force $F$ which varies with position $x$ as shown in figure. If the particle at $x equals 0$ has kinetic energy of 25 J, then the kinetic energy of the particle at $x equals 16 blank m$ is

45 J
30 J
70 J
135J

The correct answer is: 45 J

Work done=area between the graph force displacement curve and displacement
$W equals fraction numerator 1 over denominator 2 end fraction cross times 6 cross times 10 minus 5 cross times 4 plus 5 cross times 4 minus 5 cross times 2$
$W equals 20 blank J$
According to work energy theorem
$increment equals K subscript E end subscript equals W$
$K subscript E end subscript subscript f end subscript equals W plus increment K$
=20+25
=45J

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