Maths-
Range of function f(x) = 
, 
is given by -
Maths-General
Answer:The correct answer is: ]
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Related Questions to study
physics-
A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses 
and 
. Taking 
, find the work done (in joules) by the string on the block of mass during the first second after the system is released from rest
In the given condition tension in the string
And acceleration of each block
Let ‘S’ is the distance covered by block of mass in first sec
Work done by the string 
And acceleration of each block
Let ‘S’ is the distance covered by block of mass
in first sec Work done by the string A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses and . Taking , find the work done (in joules) by the string on the block of mass during the first second after the system is released from rest
physics-General
In the given condition tension in the string
And acceleration of each block
Let ‘S’ is the distance covered by block of mass in first sec
Work done by the string
And acceleration of each block
Let ‘S’ is the distance covered by block of mass
in first sec Work done by the string physics-
An object of mass 
is tied to a string of length 
and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angel 
with the vertical. Work done by the force 
is
or 
(Since, change in kinetic energy is zero)
Here,
work done by tension = 0
work done by fore of gravity
An object of mass is tied to a string of length and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angel with the vertical. Work done by the force is
physics-General
or (Since, change in kinetic energy is zero)
Here,
work done by tension = 0 work done by fore of gravityphysics-
A block of mass 
kg sliding on a smooth horizontal surface with a velocity 
meets the spring of spring constant 
fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as is returns to the original position respectively are
When block strikes the spring, the kinetic energy of block converts into potential energy of spring ie,
Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.
Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.
A block of mass kg sliding on a smooth horizontal surface with a velocity meets the spring of spring constant fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as is returns to the original position respectively are
physics-General
When block strikes the spring, the kinetic energy of block converts into potential energy of spring ie,
Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.
Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.
physics-
The relationship between the force F and position 
of a body is as shown in figure. The work done in displacing the body from 
to 
m will be
Work done=area enclosed by 
graph
=area of ABNM + area of CDEN - area of EFGH + area of HIJ
=
graph=area of ABNM + area of CDEN - area of EFGH + area of HIJ
=
The relationship between the force F and position of a body is as shown in figure. The work done in displacing the body from to m will be
physics-General
Work done=area enclosed by graph
=area of ABNM + area of CDEN - area of EFGH + area of HIJ
=
graph=area of ABNM + area of CDEN - area of EFGH + area of HIJ
=
physics-
Three objects 
and 
are kept in a straight line on a frictionless horizontal surface. These have masses 
and respectively. The object 
moves towards 
with a speed 
and makes an elastic collision with it. Thereafter, makes completely inelastic collision with . All motions occur on the same straight line. Find the final speed (in 
) of the object
After elastic collision strikes to with velocity of 
. Now collision between and is perfectly inelastic
By the law of conservation of momentum
Three objects and are kept in a straight line on a frictionless horizontal surface. These have masses and respectively. The object moves towards with a speed and makes an elastic collision with it. Thereafter, makes completely inelastic collision with . All motions occur on the same straight line. Find the final speed (in ) of the object
physics-General
After elastic collision strikes to with velocity of . Now collision between and is perfectly inelasticBy the law of conservation of momentum
physics-
The relation between the displacement 
of an object produced by the application of the variable force is represented by a graph shown in the figure. If the object undergoes a displacement from 
to 
the work done will be approximately equal to
Work done = Area under curve and displacement axis
= Area of trapezium
As the area actually is not trapezium so work done will be more than
approximately 
= Area of trapezium
As the area actually is not trapezium so work done will be more than
approximately