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General

Easy

Question

# A cubical tank 50 cm in length and 36 cm in breadth contain water. A cube of x cm edge is dropped into it and fully immersed. If the rise in water level is 15 cm, solve for x. and hence find the T.S.A of the cubical tank

- 30 ,6200
- 40 , 6200
- 30, 5400
- 40, 5400

Hint:

### TSA of cuboid = 2[lb + bh + hl]

TSA of cube = 6x2

Volume of cube = x3

Volume of cuboid = l b h

Where , l is length, b is breadth , h is height

x is side of cube

## The correct answer is: 30 ,6200

### We have given the dimensions of cubical tank

Length l = 50cm

Breadth b= 36cm

The dimensions of cube dropped are

Side = x cm

We have to find the value of x and TSA of cubical tank.

It is given that rise in water level is 15 cm , so it will be the height of the water in the cubical tank

h = 15 cm

Therefore the volume of the cube dropped will be

Volume = l b h

x^{3} = 50 36 15

= 27000

As 27000 is a cube of 30

x^{3 }= (30)^{3}

therefore, x = 30

The TSA of the cubical tank = 2[lb + bh + hl]

= 2[(50)(36) + (36)(15) + (15)(50)l]

= 2[1800 + 540 + 750]

= 2[3090]

= 6180

Which is approximately equal to 6200.

Therefore, the correct option is a) 30 , 6200.

Therefore the volume of the cube dropped will be

^{3}= 50 36 15

^{3 }= (30)

^{3}

The TSA of the cubical tank = 2[lb + bh + hl]

Which is approximately equal to 6200.

Therefore, the correct option is a) 30 , 6200.

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