In $capital delta A B C comma$ $R to the power of 2 end exponent left parenthesis blank s i n blank 2 A plus blank s i n blank 2 B plus blank s i n blank 2 C right parenthesis equals$

1 $Δ$
$3 Δ$
$2 Δ$
$4 Δ$

The correct answer is: $2 capital delta$

A equals B equals C equals 6 0 to the power of 0 end exponent comma

a equals b equals c equals 1

A equals B equals C equals 6 0 to the power of 0 end exponent comma

a equals b equals c equals 1

x equals 1.2 t to the power of 2 end exponent

x equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent

x equals 1.2 t to the power of 2 end exponent

x equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent

equals fraction numerator 1 over denominator 2 end fraction cross times 132 cross times 1200

cross times 1200

equals fraction numerator 1 over denominator 2 end fraction cross times 132 cross times 1200

cross times 1200

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In $capital delta A B C comma$ $R to the power of 2 end exponent left parenthesis blank s i n blank 2 A plus blank s i n blank 2 B plus blank s i n blank 2 C right parenthesis equals$

1 $Δ$
$3 Δ$
$2 Δ$
$4 Δ$

The correct answer is: $2 capital delta$

$3 Sin space x plus 4 Cos space x minus 6 equals 0$ then the general solution of $bold x$ =

$3 Sin space x plus 4 Cos space x minus 6 equals 0$ then the general solution of $bold x$ =

Solution of $Cot squared space theta plus open parentheses square root of 3 plus fraction numerator 1 over denominator square root of 3 end fraction close parentheses Cot space theta plus 1 equals 0$ is

Solution of $Cot squared space theta plus open parentheses square root of 3 plus fraction numerator 1 over denominator square root of 3 end fraction close parentheses Cot space theta plus 1 equals 0$ is

The general solution of $fraction numerator tan space 5 x minus tan space 4 x over denominator 1 plus tan space 5 x tan space 4 x end fraction equals 1$ is

The general solution of $fraction numerator tan space 5 x minus tan space 4 x over denominator 1 plus tan space 5 x tan space 4 x end fraction equals 1$ is

If $Sin space A equals Sin space B comma Cos space A equals Cos space B text then end text A equals$

If $Sin space A equals Sin space B comma Cos space A equals Cos space B text then end text A equals$

In $capital delta A B C comma$ $capital sigma a to the power of 3 end exponent blank c o s blank$ (B-C) $equals$

In $capital delta A B C comma$ $capital sigma a to the power of 3 end exponent blank c o s blank$ (B-C) $equals$

If $cot space theta minus tan space theta equals 2$ then principal value of $theta$

If $cot space theta minus tan space theta equals 2$ then principal value of $theta$

If $\sqrt{3} \cos θ - \sin θ = 1$ then $θ =$

If $\sqrt{3} \cos θ - \sin θ = 1$ then $θ =$

If $straight A$ and $B$ are acute angles such that $Sin space A equals Sin squared space B$ and $2 Cos squared space A equals 3 Cos squared space B$ then $A equals$

If $straight A$ and $B$ are acute angles such that $Sin space A equals Sin squared space B$ and $2 Cos squared space A equals 3 Cos squared space B$ then $A equals$

Three persons $P comma Q$ and $R$ of same mass travel with same speed $u$ such that each one faces the other always. After how much time will they meet each other?

Three persons $P comma Q$ and $R$ of same mass travel with same speed $u$ such that each one faces the other always. After how much time will they meet each other?

In the relation $straight P equals alpha over beta straight e to the power of fraction numerator alpha z over denominator k theta end fraction end exponent$ P is pressure, Z is distance, k is Boltzmann constant and $theta$ is the temperature. The dimensional formula of β b will be:

In the relation $straight P equals alpha over beta straight e to the power of fraction numerator alpha z over denominator k theta end fraction end exponent$ P is pressure, Z is distance, k is Boltzmann constant and $theta$ is the temperature. The dimensional formula of β b will be:

The number of values of k for which the system of equations $left parenthesis k plus 1 right parenthesis x plus 8 y equals 4 k comma k x plus left parenthesis k plus 3 right parenthesis y equals 3 k$ $negative 1$ has infinite number of solutions is

The number of values of k for which the system of equations $left parenthesis k plus 1 right parenthesis x plus 8 y equals 4 k comma k x plus left parenthesis k plus 3 right parenthesis y equals 3 k$ $negative 1$ has infinite number of solutions is

The value of λ such that the system $x minus 2 y plus z equals negative 4 comma 2 x minus y plus 2 z equals 2 comma x plus y plus lambda z equals 4$
has no solution is

The value of λ such that the system $x minus 2 y plus z equals negative 4 comma 2 x minus y plus 2 z equals 2 comma x plus y plus lambda z equals 4$
has no solution is