Maths-
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Question

The castesian equation of r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p is

  1. x s i n space alpha plus y s i n space alpha equals p    
  2. x c o s space alpha plus y s i n space alpha equals p    
  3. x c o s space alpha minus y s i n space alpha equals p    
  4. x c o s space alpha plus y c o s space alpha equals p    

Hint:

The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. Here we have to find the cartesian equation of r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p.

The correct answer is: x c o s space alpha plus y s i n space alpha equals p


    A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:
    ax² + bx + c = 0
    where a, b, and c are constant terms and x is the unknown variable.
    Now we have given the equation as r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p.
    Now we know that:
    cos space left parenthesis space theta space minus space alpha space right parenthesis equals cos space theta space cos space alpha space plus space sin space theta space sin space alpha.
    So applying this, we get:
    r left parenthesis cos space theta space cos space alpha space plus space sin space theta space sin space alpha right parenthesis equals p
    Now lets substitute x=rcosθ and y=rsinθ, we get:
    r cos space theta space cos space alpha space plus space r sin space theta space sin space alpha right parenthesis equals p
x space cos space alpha space plus space y space sin space alpha space equals space p


     

    Here we used the concept of quadratic equations and solved the problem. We also understood the concept of trigonometric ratios and used the formula to find the equation. So the equation is x c o s space alpha plus y s i n space alpha equals p.

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