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Maths-

General

Easy

Question

The value of $open vertical bar table row cell 1 to the power of 2 end exponent end cell cell 2 to the power of 2 end exponent end cell cell 3 to the power of 2 end exponent end cell row cell 2 to the power of 2 end exponent end cell cell 3 to the power of 2 end exponent end cell cell 4 to the power of 2 end exponent end cell row cell 3 to the power of 2 end exponent end cell cell 4 to the power of 2 end exponent end cell cell 5 to the power of 2 end exponent end cell end table close vertical bar$ is

8
– 8
400
1

The correct answer is: – 8

$open vertical bar table row cell 1 to the power of 2 end exponent end cell cell 2 to the power of 2 end exponent end cell cell 3 to the power of 2 end exponent end cell row cell 2 to the power of 2 end exponent end cell cell 3 to the power of 2 end exponent end cell cell 4 to the power of 2 end exponent end cell row cell 3 to the power of 2 end exponent end cell cell 4 to the power of 2 end exponent end cell cell 5 to the power of 2 end exponent end cell end table close vertical bar$ {Operate $R subscript 3 end subscript rightwards arrow R subscript 3 end subscript minus R subscript 2 end subscript$ , $R subscript 2 end subscript rightwards arrow R subscript 2 end subscript minus R subscript 1 end subscript$ }
= $open vertical bar table row 1 4 9 row 3 5 7 row 5 7 9 end table close vertical bar equals 1 left parenthesis 45 minus 49 right parenthesis minus 4 left parenthesis 27 minus 35 right parenthesis plus 9 left parenthesis 21 minus 25 right parenthesis$
= $negative 4 plus 32 minus 36 equals negative 8$ .

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