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Maths-

General

Easy

Question

Period of tan 4x+sec 4x is

$2 π$
$\frac{3 π}{2}$
$π$
$\frac{π}{2}$

Hint:

In this question, we have to find the period of the trigonometric given. For that first we will find the period of trigonometric identities separately and later to find the period of sum, we will find the LCM of the periods derived.

The correct answer is: $pi over 2$

f(x)= tan 4x + sec 4x
Period of tan 4x = $fraction numerator straight pi over denominator open vertical bar 4 close vertical bar end fraction equals straight pi over 4$
Period of sec 4x= $fraction numerator 2 straight pi over denominator open vertical bar 4 close vertical bar end fraction equals straight pi over 2$
So, period of f(x)=LCM of $straight pi over 4 comma straight pi over 2 equals straight pi over 2$

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