Maths-

General

Easy

Question

# The minimum and maximum values of are

- -1,1
- 1,8
- -3,3

Hint:

### In this question, we have to find the maximum and minimum value of the given function. As we know, minimum and maximum value of a sin x + b cos x is , so we can now find the required value.

## The correct answer is: -3,3

### f(x) =

As minimum and maximum value of a sin x + b cos x is

So, minimum value

Maximum value =

### Related Questions to study

chemistry-

(A) and(C) are different compound s and rotate the plane-polarised light in the same direction, andboth are dextrorotatory. Both (A) and(C) do not show diastereomers, whichof the following statements are correct?

(A) and(C) are different compound s and rotate the plane-polarised light in the same direction, andboth are dextrorotatory. Both (A) and(C) do not show diastereomers, whichof the following statements are correct?

chemistry-General

chemistry-

### Which of the following dienes and dienophiles could be used to synthesise the following compound (A) ?

### Which of the following dienes and dienophiles could be used to synthesise the following compound (A) ?

chemistry-General

Maths-

### 16 sin

### 16 sin

Maths-General

physics-

### Five conductors are meeting at a point x as shown in the figure. What is the value of current in fifth conductor?

According to Kirchhoff’s first law

(5A)+(4A)+(-3A)+(-5A)+I=0

Or I=-1A

(5A)+(4A)+(-3A)+(-5A)+I=0

Or I=-1A

### Five conductors are meeting at a point x as shown in the figure. What is the value of current in fifth conductor?

physics-General

According to Kirchhoff’s first law

(5A)+(4A)+(-3A)+(-5A)+I=0

Or I=-1A

(5A)+(4A)+(-3A)+(-5A)+I=0

Or I=-1A

physics-

### The figure shows a network of currents. The magnitude of current is shown here. The current I will be

Regarding Kirchhoff’s junction rule, the circuit can be redrawn as

Current in arm,

Current in arm,

Current in arm,

Hence,

Current in arm,

Current in arm,

Current in arm,

Hence,

### The figure shows a network of currents. The magnitude of current is shown here. The current I will be

physics-General

Regarding Kirchhoff’s junction rule, the circuit can be redrawn as

Current in arm,

Current in arm,

Current in arm,

Hence,

Current in arm,

Current in arm,

Current in arm,

Hence,

physics-

### The equivalent resistance between the terminals in the following circuit is

10 in series with 10 will gives

(10+10)=20

and 10 in series with 10 will gives

(10+10)=20

20 in parallel with 20 will gives

Resistance in series between points A and D

=5+10+5

=20

### The equivalent resistance between the terminals in the following circuit is

physics-General

10 in series with 10 will gives

(10+10)=20

and 10 in series with 10 will gives

(10+10)=20

20 in parallel with 20 will gives

Resistance in series between points A and D

=5+10+5

=20

physics-

### The equivalent resistance between points A and B of an infinite network of resistances, each of 1, connected as shown is

Let be the equivalent resistance of entire network between A and B. Hence, we have

resistance of parallel combination of 1 and

resistance of parallel combination of 1 and

### The equivalent resistance between points A and B of an infinite network of resistances, each of 1, connected as shown is

physics-General

Let be the equivalent resistance of entire network between A and B. Hence, we have

resistance of parallel combination of 1 and

resistance of parallel combination of 1 and

Maths-

### The period of is

Period of sin

As we know, if the period of f(x) is T then the period of g(f(x)) is also T.

So, period of sin(sin) =2

As we know, if the period of f(x) is T then the period of g(f(x)) is also T.

So, period of sin(sin) =2

### The period of is

Maths-General

Period of sin

As we know, if the period of f(x) is T then the period of g(f(x)) is also T.

So, period of sin(sin) =2

As we know, if the period of f(x) is T then the period of g(f(x)) is also T.

So, period of sin(sin) =2

Maths-

### The period of is

f(x)=

Period of sin kx =

In numerator,

period of sin ()=

In denominator,

period of sin ()=

So, the period of f(x) is 1.

Period of sin kx =

In numerator,

period of sin ()=

In denominator,

period of sin ()=

So, the period of f(x) is 1.

### The period of is

Maths-General

f(x)=

Period of sin kx =

In numerator,

period of sin ()=

In denominator,

period of sin ()=

So, the period of f(x) is 1.

Period of sin kx =

In numerator,

period of sin ()=

In denominator,

period of sin ()=

So, the period of f(x) is 1.

Maths-

### Period of tan 4x+sec 4x is

f(x)= tan 4x + sec 4x

Period of tan 4x =

Period of sec 4x=

So, period of f(x)=LCM of

Period of tan 4x =

Period of sec 4x=

So, period of f(x)=LCM of

### Period of tan 4x+sec 4x is

Maths-General

f(x)= tan 4x + sec 4x

Period of tan 4x =

Period of sec 4x=

So, period of f(x)=LCM of

Period of tan 4x =

Period of sec 4x=

So, period of f(x)=LCM of

Maths-

### The cotangent function whose period is

Period of cot (k x) =

given,

So, cotangent function whose period is .

given,

So, cotangent function whose period is .

### The cotangent function whose period is

Maths-General

Period of cot (k x) =

given,

So, cotangent function whose period is .

given,

So, cotangent function whose period is .

physics-

### Thirteen resistances each of resistance R are connected in the circuit as shown in the figure. The effective resistance between points A and B is

Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

### Thirteen resistances each of resistance R are connected in the circuit as shown in the figure. The effective resistance between points A and B is

physics-General

Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

Now, there are four triangles

Effective resistance of each triangle

Now the given circuit reduced to

Therefore, effective resistance between A and B,

physics-

### Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across The effective resistance across and the current through the arm will be

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

### Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across The effective resistance across and the current through the arm will be

physics-General

The equivalent circuit is shown as

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

We can emit the resistance in the arm DF as balance condition is satisfied.

Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

are in parallel

R’’’=3

Now, R’’’ and 3 resistances are in parallel

Moreover, V across AB=3V and resistance in the arm=3

∴ Current through the arm will be

physics-

### In the circuit shown the value of I in ampere is

We can simplify the network as shown

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

### In the circuit shown the value of I in ampere is

physics-General

We can simplify the network as shown

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

So, net resistance,

R=2.4+1.6=4.0

Therefore, current from the battery.

Now, from the circuit (b),

4I’ =6I

But =I+I’

physics-

### The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

The equation from the given graph can be written as,

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

### The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?

physics-General

The equation from the given graph can be written as,

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.

Substituting from Eq. (i), we get

Thus, graph is a straight line with positive slope and negative intercept.