General
Easy
Maths-

Let A be a set containing 10 distinct elements, then the total number of distinct functions from A to A is-

Maths-General

  1. 10 to the power of 10 end exponent    
  2. 10 factorial    
  3. 2 to the power of 10 end exponent minus 1    
  4. 2 to the power of 10 end exponent    

    Answer:The correct answer is: 10 to the power of 10 end exponent

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    Related Questions to study

    General
    maths-

    The number of bijective functions from set A to itself when a contains 106 elements-

    The number of bijective functions from set A to itself when a contains 106 elements-

    maths-General
    General
    physics-

    A particle of mass m moving with a velocity u makes an elastic one dimensional collision with a stationary particle of mass m establishing a contact with it for extremely small time T. Their force of contact increases from zero to F subscript 0 end subscript linearly in time T divided by 4, remains constant for a further time T divided by 2 and decreases linearly from F subscript 0 end subscript to zero in further time T divided by 4 as shown. The magnitude possessed by F subscript 0 end subscript is

    Change in momentum = Impulse
    = Area under force-time graph
    therefore m v equals Area of trapezium
    rightwards double arrow m v equals fraction numerator 1 over denominator 2 end fraction open parentheses T plus fraction numerator T over denominator 2 end fraction close parentheses F subscript 0 end subscript rightwards double arrow m v equals fraction numerator 3 T over denominator 4 end fraction F subscript 0 end subscript rightwards double arrow F subscript 0 end subscript equals fraction numerator 4 m u over denominator 3 T end fraction

    A particle of mass m moving with a velocity u makes an elastic one dimensional collision with a stationary particle of mass m establishing a contact with it for extremely small time T. Their force of contact increases from zero to F subscript 0 end subscript linearly in time T divided by 4, remains constant for a further time T divided by 2 and decreases linearly from F subscript 0 end subscript to zero in further time T divided by 4 as shown. The magnitude possessed by F subscript 0 end subscript is

    physics-General
    Change in momentum = Impulse
    = Area under force-time graph
    therefore m v equals Area of trapezium
    rightwards double arrow m v equals fraction numerator 1 over denominator 2 end fraction open parentheses T plus fraction numerator T over denominator 2 end fraction close parentheses F subscript 0 end subscript rightwards double arrow m v equals fraction numerator 3 T over denominator 4 end fraction F subscript 0 end subscript rightwards double arrow F subscript 0 end subscript equals fraction numerator 4 m u over denominator 3 T end fraction
    General
    physics-

    Given below is a graph between a variable force left parenthesis F right parenthesis (along y-axis) and the displacement left parenthesis X right parenthesis (along x-axis) of a particle in one dimension. The work done by the force in the displacement interval between 0 blank m and 30 blank m is

    Given below is a graph between a variable force left parenthesis F right parenthesis (along y-axis) and the displacement left parenthesis X right parenthesis (along x-axis) of a particle in one dimension. The work done by the force in the displacement interval between 0 blank m and 30 blank m is

    physics-General
    General
    physics-

    The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 blank m is

    Work done W equals area under F minus S graph
    = area of trapezium A B C D plus area of trapezium C E F D
    equals fraction numerator 1 over denominator 2 end fraction cross times open parentheses 10 plus 15 close parentheses cross times 10 plus fraction numerator 1 over denominator 2 end fraction cross times left parenthesis 10 plus 20 right parenthesis cross times 5
    equals 125 plus 75 equals 200 blank J

    The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 blank m is

    physics-General
    Work done W equals area under F minus S graph
    = area of trapezium A B C D plus area of trapezium C E F D
    equals fraction numerator 1 over denominator 2 end fraction cross times open parentheses 10 plus 15 close parentheses cross times 10 plus fraction numerator 1 over denominator 2 end fraction cross times left parenthesis 10 plus 20 right parenthesis cross times 5
    equals 125 plus 75 equals 200 blank J
    General
    physics-

    If w subscript 1 end subscript comma w subscript 2 blank a n d blank W subscript 3 end subscript end subscript represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively(as shown)in the gravitational field of a point mass m. Find the correct relation between w subscript 1 end subscript comma w subscript 2 end subscript a n d blank w subscript 3 end subscript

    Gravitational field is a conservative force field. In a conservative force field work done is path independent.
    therefore blank W subscript 1 end subscript equals W subscript 2 end subscript equals W subscript 3 end subscript

    If w subscript 1 end subscript comma w subscript 2 blank a n d blank W subscript 3 end subscript end subscript represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively(as shown)in the gravitational field of a point mass m. Find the correct relation between w subscript 1 end subscript comma w subscript 2 end subscript a n d blank w subscript 3 end subscript

    physics-General
    Gravitational field is a conservative force field. In a conservative force field work done is path independent.
    therefore blank W subscript 1 end subscript equals W subscript 2 end subscript equals W subscript 3 end subscript
    General
    physics-

    A particle is acted upon by a force Fwhich varies with position xas shown in figure. If the particle at x equals 0 has kinetic energy of 25 J, then the kinetic energy of the particle at x equals 16 blank m is

    Work done=area between the graph force displacement curve and displacement
    W equals fraction numerator 1 over denominator 2 end fraction cross times 6 cross times 10 minus 5 cross times 4 plus 5 cross times 4 minus 5 cross times 2
    W equals 20 blank J
    According to work energy theorem
    increment equals K subscript E end subscript equals W
    K subscript E end subscript subscript f end subscript equals W plus increment K
    =20+25
    =45J

    A particle is acted upon by a force Fwhich varies with position xas shown in figure. If the particle at x equals 0 has kinetic energy of 25 J, then the kinetic energy of the particle at x equals 16 blank m is

    physics-General
    Work done=area between the graph force displacement curve and displacement
    W equals fraction numerator 1 over denominator 2 end fraction cross times 6 cross times 10 minus 5 cross times 4 plus 5 cross times 4 minus 5 cross times 2
    W equals 20 blank J
    According to work energy theorem
    increment equals K subscript E end subscript equals W
    K subscript E end subscript subscript f end subscript equals W plus increment K
    =20+25
    =45J
    General
    physics-

    A vertical spring with force constant K is fixed on a table. A ball of mass mat a height h above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance d. The net work done in the process is

    Gravitational potential energy of ball gets converted into elastic potential energy of the spring m g open parentheses h plus d close parentheses equals fraction numerator 1 over denominator 2 end fraction K d to the power of 2 end exponent
    Net work done equals m g open parentheses h plus d close parentheses minus fraction numerator 1 over denominator 2 end fraction K d to the power of 2 end exponent equals 0

    A vertical spring with force constant K is fixed on a table. A ball of mass mat a height h above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance d. The net work done in the process is

    physics-General
    Gravitational potential energy of ball gets converted into elastic potential energy of the spring m g open parentheses h plus d close parentheses equals fraction numerator 1 over denominator 2 end fraction K d to the power of 2 end exponent
    Net work done equals m g open parentheses h plus d close parentheses minus fraction numerator 1 over denominator 2 end fraction K d to the power of 2 end exponent equals 0
    General
    physics-

    Figure shows the F-xgraph. Where F is the force applied and x is the distance covered

    By the body along a straight line path. Given that F is in n e w t o n and x blankin m e t r e, what is the work done?

    Work done =area under curve and displacement axis
    equals 1 cross times 10 minus 1 cross times 10 plus 1 cross times 10 equals 10 blank J

    Figure shows the F-xgraph. Where F is the force applied and x is the distance covered

    By the body along a straight line path. Given that F is in n e w t o n and x blankin m e t r e, what is the work done?

    physics-General
    Work done =area under curve and displacement axis
    equals 1 cross times 10 minus 1 cross times 10 plus 1 cross times 10 equals 10 blank J
    General
    maths-

    Domain of definition of the functionf left parenthesis x right parenthesis equals fraction numerator 3 over denominator 4 minus x to the power of 2 end exponent end fraction plus l o g subscript 10 end subscript invisible function application open parentheses x to the power of 3 end exponent minus x close parentheses, is

    Domain of definition of the functionf left parenthesis x right parenthesis equals fraction numerator 3 over denominator 4 minus x to the power of 2 end exponent end fraction plus l o g subscript 10 end subscript invisible function application open parentheses x to the power of 3 end exponent minus x close parentheses, is

    maths-General
    General
    physics-

    Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all forces on the particle is

    Initial velocity of particle, v subscript i end subscript equals 20 blank m s to the power of negative 1 end exponent
    Final velocity of the particle, v subscript f end subscript equals 0
    According to work-energy theorem,
    W subscript n e t end subscript equals increment K E equals K subscript f end subscript minus K subscript i end subscript
    equals fraction numerator 1 over denominator 2 end fraction m left parenthesis v subscript f end subscript superscript 2 end superscript minus v subscript i end subscript superscript 2 end superscript right parenthesis
    equals fraction numerator 1 over denominator 2 end fraction cross times 2 left parenthesis 0 to the power of 2 end exponent minus 20 to the power of 2 end exponent right parenthesis
    equals negative 400 blank J

    Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all forces on the particle is

    physics-General
    Initial velocity of particle, v subscript i end subscript equals 20 blank m s to the power of negative 1 end exponent
    Final velocity of the particle, v subscript f end subscript equals 0
    According to work-energy theorem,
    W subscript n e t end subscript equals increment K E equals K subscript f end subscript minus K subscript i end subscript
    equals fraction numerator 1 over denominator 2 end fraction m left parenthesis v subscript f end subscript superscript 2 end superscript minus v subscript i end subscript superscript 2 end superscript right parenthesis
    equals fraction numerator 1 over denominator 2 end fraction cross times 2 left parenthesis 0 to the power of 2 end exponent minus 20 to the power of 2 end exponent right parenthesis
    equals negative 400 blank J
    General
    physics-

    A frictionless track A B C D E ends in a circular loop of radius R. A body slides down the track from point A which is it a height h equals 5 blank c m. Maximum value of R for the body to successfully complete the loop is

    Condition for vertical looping
    h equals fraction numerator 5 over denominator 2 end fraction r equals 5 c m blank therefore r equals 2 blank c m

    A frictionless track A B C D E ends in a circular loop of radius R. A body slides down the track from point A which is it a height h equals 5 blank c m. Maximum value of R for the body to successfully complete the loop is

    physics-General
    Condition for vertical looping
    h equals fraction numerator 5 over denominator 2 end fraction r equals 5 c m blank therefore r equals 2 blank c m
    General
    physics-

    The force acting on a body moving along x-axis varies with the position of the particle as shown in the fig

    The body is in stable equilibrium at

    When particle moves away from the origin then at position x equals x subscript 1 end subscript force is zero and at x greater than x subscript 1 end subscript, force is positive (repulsive in nature) so particle moves further and does not return back to original position i. e. the equilibrium is not stable Similarly at position x equals x subscript 2 end subscript force is zero and at x greater than x subscript 2 end subscript, force is negative (attractive in nature) So particle return back to original position i. e. the equilibrium is stable

    The force acting on a body moving along x-axis varies with the position of the particle as shown in the fig

    The body is in stable equilibrium at

    physics-General
    When particle moves away from the origin then at position x equals x subscript 1 end subscript force is zero and at x greater than x subscript 1 end subscript, force is positive (repulsive in nature) so particle moves further and does not return back to original position i. e. the equilibrium is not stable Similarly at position x equals x subscript 2 end subscript force is zero and at x greater than x subscript 2 end subscript, force is negative (attractive in nature) So particle return back to original position i. e. the equilibrium is stable
    General
    physics-

    The pointer reading v divided by s load graph for a spring balance is as given in the figure. The spring constant is

    Spring constant k equals fraction numerator F over denominator x end fraction equals Slope of curve
    therefore k equals fraction numerator 4 minus 1 over denominator 30 end fraction equals fraction numerator 3 over denominator 30 end fraction equals 0.1 blank k g divided by c m

    The pointer reading v divided by s load graph for a spring balance is as given in the figure. The spring constant is

    physics-General
    Spring constant k equals fraction numerator F over denominator x end fraction equals Slope of curve
    therefore k equals fraction numerator 4 minus 1 over denominator 30 end fraction equals fraction numerator 3 over denominator 30 end fraction equals 0.1 blank k g divided by c m
    General
    physics-

    The force F acting on a particle moving in a straight line is shown in figure. What is the work done by the force on the particle in the 1st meter of the trajectory

    Work done open parentheses W close parentheses equals Area under curve of F-x graph
    = Area of triangle O A B equals fraction numerator 1 over denominator 2 end fraction cross times 5 cross times 1 equals 2.5 blank J

    The force F acting on a particle moving in a straight line is shown in figure. What is the work done by the force on the particle in the 1st meter of the trajectory

    physics-General
    Work done open parentheses W close parentheses equals Area under curve of F-x graph
    = Area of triangle O A B equals fraction numerator 1 over denominator 2 end fraction cross times 5 cross times 1 equals 2.5 blank J
    General
    maths-

    Range of function f(x) = fraction numerator x to the power of 2 end exponent plus 2 x plus 3 over denominator x end fraction, x element of times R is given by -

    ]
    (C) left parenthesis negative infinity comma 2 minus 2 square root of 3 right square bracket union left square bracket 2 plus 2 square root of 3 comma infinity right parenthesis

    Range of function f(x) = fraction numerator x to the power of 2 end exponent plus 2 x plus 3 over denominator x end fraction, x element of times R is given by -

    maths-General
    ]
    (C) left parenthesis negative infinity comma 2 minus 2 square root of 3 right square bracket union left square bracket 2 plus 2 square root of 3 comma infinity right parenthesis