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# The equation of normal in terms of slope m to the parabola (y – 2)^{2} = 4 (x – 3)

- y = mx – 2m – m
^{3}
- y = mx – 5m – m
^{3} + 2
- y – 2 = mx – 2m – m
^{3}
- none of these

^{3}^{3}+ 2^{3}## The correct answer is: y = mx – 5m – m^{3} + 2

### To find the equation of normal.

Given , parabola (Y – 2)2 = 4 (X – 3)

Using equation of normal to parabola is .

Here comparing the equations of parabola we get a = 1; y = (Y – 2) and x = (X – 3)

Then substitute them in

Therefore, Using equation of normal to parabola is y = mx – 5m – m3 + 2 is the equation of normal in terms of slope.

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