Blog Post

Grade 1

Grade 2

Grade 3

Grade 4

Grade 5

Grade 6

Grade 7

Grade 8

Grade 9

Grade 10

Grade 11

Grade 12

<h3 class="wp-block-heading">Key Concepts </h3>



• Centrifugal force 



• Acceleration 



• Angular acceleration



<h2 class="wp-block-heading">Introduction:&nbsp;</h2>



In this session we are going to study centrifugal force. We are going to differentiate between acceleration in rectilinear motion and uniform circular motion, and derive a relation to calculate the same.&nbsp;



<h3 class="wp-block-heading">Centrifugal force:&nbsp;</h3>



An outward force on a rotating or revolving body is called a centrifugal force. Centrifugal means “center-fleeing.” Centrifugal force does not pull an object outward. This is a misconception.&nbsp;<div class="fillWidthInMob"><a loading='lazy' class="showAdInAllRes" data-toggle="modal" data-target=#homeLeadForm data-heading="Get Expert Guidance" href="#"><img class="img-fluid" alt="parallel" src=https://a.storyblok.com/f/128066/1100x230/00b28b4876/11-applying-for-collages_leaderboard-1100x230.jpg /></a></div>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" src="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture10-4.jpg" alt=" Centrifugal force " class="wp-image-11065" width="339" height="331" srcset="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture10-4.jpg 654w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture10-4-300x293.jpg 300w" sizes="auto, (max-width: 339px) 100vw, 339px" /></figure></div>


Newton’s First Law says that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. It is not due to any real force rather due to inertia. The centrifugal force is not a true force as it is an effect of rotation. It is equal and opposite to the centripetal force&nbsp;


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture11-4-1024x502.jpg" alt="Centripetal force vs centrifugal force " class="wp-image-11067" width="463" height="226" srcset="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture11-4-1024x502.jpg 1024w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture11-4-300x147.jpg 300w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture11-4-768x376.jpg 768w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture11-4.jpg 1118w" sizes="auto, (max-width: 463px) 100vw, 463px" /></figure></div>


<h3 class="wp-block-heading">Acceleration:&nbsp;</h3>



It is defined as the rate of change of velocity.&nbsp;&nbsp;



Acceleration =



change&nbsp;in&nbsp;velocityTimechange&nbsp;in&nbsp;velocityTime



Acceleration exists when there is a change in velocity. Velocity is a vector quantity. It has both magnitude as well as direction associated with it.&nbsp;&nbsp;<div class="fillWidthInMob"><a loading='lazy' class="showAdInAllRes" data-toggle="modal" data-target=#homeLeadForm data-heading="Get Expert Guidance" href="#"><img class="img-fluid" alt="parallel" src=https://a.storyblok.com/f/128066/1100x230/00b28b4876/11-applying-for-collages_leaderboard-1100x230.jpg /></a></div>



If u is the initial velocity and v is the final velocity and t is the time taken then the formula is :&nbsp;



a =



v−utv−ut



This formula is used for linear motion, for the uniform circular motion we calculate the angular acceleration.&nbsp;



<h3 class="wp-block-heading">Centrifugal Acceleration:</h3>



It depends on the radius of the circle and the speed of the object.&nbsp;



It is denoted by “ac” Its unit is “m/s .”&nbsp;



<figure class="wp-block-image size-large is-resized"><img loading="lazy" decoding="async" src="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture12-4-1024x270.jpg" alt="" class="wp-image-11071" width="490" height="129" srcset="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture12-4-1024x270.jpg 1024w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture12-4-300x79.jpg 300w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture12-4-768x203.jpg 768w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture12-4-1536x405.jpg 1536w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture12-4.jpg 1600w" sizes="auto, (max-width: 490px) 100vw, 490px" /></figure>



<h3 class="wp-block-heading">Questions and answers&nbsp;</h3>



Question 1: Draw the direction of the centrifugal force if the object is released from its orbit at point 1 and 2.&nbsp;


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture13-4-1013x1024.jpg" alt="question 1 figure " class="wp-image-11081" width="274" height="277" srcset="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture13-4-1013x1024.jpg 1013w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture13-4-297x300.jpg 297w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture13-4-768x776.jpg 768w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture13-4.jpg 1176w" sizes="auto, (max-width: 274px) 100vw, 274px" /></figure></div>


Answer:&nbsp;



For object 1 it will go in horizontal direction towards the right.&nbsp;&nbsp;



For object 2 it will go vertically down.


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture14-4-975x1024.jpg" alt="Answer 1 figure " class="wp-image-11083" width="286" height="300" srcset="https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture14-4-975x1024.jpg 975w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture14-4-286x300.jpg 286w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture14-4-768x806.jpg 768w, https://www.turito.com/learn-internal/wp-content/uploads/2022/08/Picture14-4.jpg 1423w" sizes="auto, (max-width: 286px) 100vw, 286px" /></figure></div>


Question 2: The speed of a boy of weight 40 Kg in a merry-go-round of radius 20 m is 40 m/s. What is the centrifugal force experienced by the system?&nbsp;



Answer:&nbsp;



Given that:&nbsp;&nbsp;



Speed of boy = 40 m/s&nbsp;



Radius of merry go round = 20 m&nbsp;



Mass of boy = 40 kg&nbsp;



Using formula,



FC=mv2r𝑭𝑪=𝒎𝒗𝟐𝒓



==



40



(40220)40220 =



40×40×402040×40×4020 = 3200 N&nbsp;&nbsp;



Question 3: What is the centripetal acceleration of an object if it going round in circles with velocity of 20 km/h and comes to rest in 20 s. The radius of the circle is 20 m.&nbsp;&nbsp;



Answer:&nbsp;



Given that:&nbsp;&nbsp;



Initial velocity,&nbsp;



u = 20 km/h&nbsp; = 20



&nbsp;×10003600&nbsp;&nbsp;×10003600&nbsp;



=



200&nbsp;m/s36200&nbsp;m/s36



Final velocity, v = 0 m/s&nbsp;



Radius, r = 20 m&nbsp;



Time period t = 20 s&nbsp;



aC=v2raC=v2r



=



(20036)2



××



120&nbsp; =



200&nbsp;×20020&nbsp;×36&nbsp;×&nbsp;36 = 1.54 m/s2



<h3 class="wp-block-heading">Summary </h3>



<ul class="wp-block-list"><li>An outward force on a rotation or revolving body is called a Centrifugal force. </li><li>It is pointed outwards. </li><li> Centrifugal force is an inertial force. </li></ul>



Fc = Mv2/R



<ul class="wp-block-list"><li>Centrifugal acceleration depends upon velocity and radius.</li></ul>



ac=v2/r