One of the most challenging yet interesting things to do would be to know how to divide polynomials. This might seem like an intimidating operation to perform. However, it would be surprisingly simple if one could recall all the basic formulae and rules regarding the long division of integers.

At first, one needs to understand what a monomial is. Then, they should know about how it is closely related to polynomials. Finally, you should have an idea of what happens between two polynomials in an equation.

**Polynomials**

A polynomial is identified as an expression used in algebra (an important branch of mathematics). It is constructed upon two or more terms that are added, multiplied, or subtracted. It contains constants, exponents, variables, and coefficients. It also has operators namely subtraction and addition.

Polynomials must not contain fractional or negative exponents. Some of the examples are given below:

- 8 x
^{2}– 5 x + 8 - 7 y
^{3}+ 12 y^{2}– 2 y + 1 - 6 z
^{2}– z – 1 - 2 x
^{3}+ 6 x^{2}– 4 x + 10

**Polynomials are of three major types. They are monomial, binomial and trinomial.**

**Monomial**

Monomials are described as algebraic expressions that contain only one term. Some examples of monomials are,

5 x^{3}, 7 x, – 2 y, 2z, etc.

**Binomials**

Binomials are mathematical expressions that consist of two terms in it. It is either separated by a subtraction (-) or an addition symbol (+).

Few examples are, 5 x^{2} +6, y^{3} – 2y, 2 x y + 4 y, x^{3} – 5, etc.

**Trinomials**

It is nothing but an algebraic expression that contains three terms in it. For example,

9 x^{3} – 2 x^{2} + 7, 4 y^{2} – 2y – 2, 12 x – 6 y + 2, 3 x y + 2 z^{3} – 19.

**How to divide polynomials?**

In arithmetic operations, the division is utilized to split a quantity into equal amounts. The division is commonly considered reverse multiplication or repeated subtraction.

In math, there are two ways of dividing polynomials. They are synthetic division and dividing polynomials long division method. The synthetic method is known to be a fun way of dividing polynomials. On the contrary, the long division method is tiresome and consists of a long process.

**Types of polynomial division**

After having a brief look at how to divide polynomials, the next thing one should know is what the different types of polynomial divisions available are. There are 4 basic types of division in polynomials. They are:

- Dividing a monomial using another monomial
- Dividing polynomials by monomials
- Dividing polynomials by binomials
- Dividing a polynomial using another polynomial

**Dividing a monomial by another monomial**

It is common to divide the coefficient at first. Later on, one needs to apply the quotient law to the variables while processing the division of a monomial using another monomial.

The quotient law is x^{m}/x^{n} = x^{m-n.}

An important note is that any variable or number that contains a power of 0 is 1. To give an example, y0 = 1. Let us have a wider look at more examples:

**Divide**20 y^{2}by 10 y

**Solution:** 1^{st} we divide the coefficients of the given terms.

20/10 = 2

Then divide the variables with the help of the quotient rule:

y^{2}/y = y^{2-1}

= y

The next step is, multiplying the quotient of the variables by the quotient of the coefficients:

= 2 y

In an alternative way, 20 y^{2}/10 y =5 * 2 * 2 * y * y/5 * 2 * y

Canceling y, 5, and 2 since they are common terms and are present in both the numerator as well as the denominator,

20 y^{2}/10 y = 2 y

**Divide**^{3}y^{3}z by 5 x y^{2}z

**Solution***:* Start by dividing the coefficients normally and then use the quotient law to divide the variables,

25 x^{3} y^{3} z / 5 x y^{2} z = (25/5)x^{3-1} y^{3-2} z^{1-1}

= 5 x^{2} y z0

= 5 x^{2} y (final answer)

**Divide**

**Solution***: *Firstly, start dividing the coefficient normally. After doing so, to divide the variables, utilize the quotient law,

63 x^{2} y^{3} z^{2} / 7 x y^{2} z = (63/7) x^{2 -1} y^{3-2} z^{2 -1}

= 9 x y z (final answer)

**Dividing polynomials by monomials**

It is simple to divide polynomials using a monomial. First, one needs to divide each term of the polynomial separately with a monomial. After that, to obtain the answer, we simply add the quotient of each operation.

**Let us understand thoroughly using few examples:**

**Divide**^{2}– 6 x y + 9 x^{2}y z by 3 y

12 y^{2 }– 6 x y + 9 x2/3 y = 12 y^{2}3/ y – 6 x y/3 y + 9 x^{2} y z/3 y

**Answer** = 4 y – 2 x + 3 x^{2} z

**Divide**^{2}z^{3}+ 25 x^{3}y^{2}z – 15 x^{2}y z^{2}by 5 x y z

40 x y^{2 }z^{3} + 25 x^{3} y^{2 }z – 15 x^{2} y z^{2}/5 x y z

= 40 x y^{2} z^{3}/5 x y z + 25 x^{3} y^{2} z/5 x y z – 15 x^{2 }y z^{2}/5 x y z

**Answer:*** *8 y z^{2 }+ 5 x^{2} y – 3 x z

**Divide**^{3 }+ 48 x^{3}y^{3}z – 16 x^{2 }y z^{2}by 8 x z

32 x y z^{3} + 48 x^{3} y^{3} z – 16 x^{2} y z^{2}/8 x z

= 32 x y z^{3}/8 x z + 48 x^{3} y^{3} z/8 x z – 16 x^{2} y z^{2}/8 x z

**Answer: **4 y z^{2} + 6 x^{2} y^{3} – 2 x y z

**Divide**8 m^{4}n^{2}+ 16 m n^{3}– 12 m^{3}n^{2}by 4 m n^{2}

8 m^{4} n^{2} + 16 m n^{3} – 12 m^{3} n^{2}/ 4 m n^{2} = 8 m^{4} n^{2}/4 m n^{2} + 16 m n^{3}/4 m n^{2} – 12 m^{3} n^{2}/4 m n^{2}

**Answer:*** *2 m^{3} + 4 n – 3 m^{2}

**Divide**b^{3}+ a b^{2}– a^{3}b^{2}by b^{2}

b^{3} + a b^{2} – a^{3} b^{2}b^{2}

= b^{3}/b^{2} + a b^{2}/b^{2 }– a^{3 }b^{2}/b^{2}

**Answer: **b + a – a^{3}

**Polynomial division algorithm**

Consider m (y) and n (y) are any two polynomials with n y≠0. The polynomials q (y) and r (y) can be found by:

m (y) = n (y) * q (y)+ r (y)

Here,

r (y) = 0 or degree of r (y) < degree of n (y)

The result obtained is known as the division algorithm for polynomials.

As a result of the previous example, one can verify this algorithm as:

m (y)=3 y^{3} + y^{2} + 2 y + 5

n (y) = y^{2} + 2 y + 1

Quotient = q (y) = 3 y – 1

Remainder = r (y) = 9 y + 10

Now,

n (y) * q (y) + r (y) = (y^{2 }+ 2 y + 1) * (2 y – 5) + (9 y + 10)

= 3 y^{3} + 6 y^{2 }+ 3 y – 5 y^{2} – 10 y – 5 + 9 + 10

= 3 y^{3} + y^{2} + 2 y + 5

= m (y)

Therefore, the division algorithm has been verified.

**Dividing Polynomials using long division**

Dividing polynomials using long division is a very complex technique. Although, it is a very reliable and suitable method to obtain results while dividing polynomials. This method is practical for all polynomial equations.

This process is very similar to dividing numbers or integers. It requires the assistance of the long division method. The following procedures should be followed while dividing polynomials using long division:

- Firstly, rearrange the divisor in descending order. Then arrange the divider in the same way.
- Secondly, divide the first term of the dividend by the divisor’s first term. This will help obtain the first quotient term.
- Now identify the product of the entire divisor’s term. Then find the first term quotient. After doing so, subtract the answer of the dividend.
- If it still contains a remainder, keep on proceeding to the 3
^{rd}step until obtaining zero as the remainder. If not, we will end up obtaining a solution having a lesser degree than that of the divisor.

**Let us see an example of the same:**

**Example:*** *Using the long division technique, divide the given polynomials: 3 y^{3}-8 y+5 by y-1

**Dividing polynomials with remainders**

To understand the concept of dividing polynomials with remainders, let us consider:

a (y) = 5 y^{2 }– 6 y + 10 y – 2 and b (y) = 15 y^{3} + 2 x

In this, while dividing a by b, one can determine the remainder polynomial (r) and unique quotient polynomial (q) which is capable of satisfying the following equation:

a (y)/b (y) = q (y) + r (y)/b (y)

Here the degree of b (y) is higher than the degree of r (y).

**Conclusion**

From this article, one can have a detailed understanding and idea of what exactly is a polynomial. It also provides knowledge on how to divide polynomials. We then discussed dividing polynomials by monomials, dividing polynomials by long division, etc. Finally, we have seen the topic named polynomials with remainders. Other than that, examples are also provided for all the discussed concepts. This would help students understand all these concepts in a much clearer way.