## Key Concepts

- Find the volume of a solid.
- Use volume of a pyramid.
- Use trigonometry to find the volume of a cone.

### Introduction

#### Volume of a Pyramid

The volume V of a pyramid is,

**V = 1/3 x Bh**, where B is the area of the base and h is the height.

#### Volume of a Cone

The volume of a cone is,

**V = 1/3 x Bh** = πr^{2}h, where B is the area of the base, h is the height and r are the radius of the base.

### Find the volume of a solid

**Example 1:**

Find the volume of the following solid.

**Solution:**

The base can be divided into six equilateral triangles. Using the formula of an equilateral triangle,

¼ √3 • s^{2}, the area of the base B can be found as follows:

6.1/4√3.s^{2} = 6.1/4√3.3^{2} = 27/2√3cm^{2}

Use theorem to find the volume of the pyramid.

V = 1/3Bh (Formula for volume of pyramid)

= 1/3(27/2 √3)(4) (Substitute)

= 18√3 (Simplify)

So, the volume of the pyramid is 18√3, or about 31.2 cubic centimeters.

**Example 2:**

Find the volume of the following solid.

**Solution**

Use the formula for the volume of a cone.

V = 1/3Bh (Formula for volume of cone)

V= 1/3(πr^{2})h (Base area equal πr^{2})

V= 13(π 1.5^{2})(4) (Substitute)

V=3π (Simplify)

So, the volume of the cone is 3𝝅, or about 9.42 cubic inches.

### Use volume of a pyramid

**Example 3:**

A greenhouse has the shape of a square pyramid. The height of the greenhouse is 18 yards and volume is 5400 yd^{3}. What is the side length of the square base of the greenhouse?

**Solution:**

*V =* 1/3 Bh à Write the formula.

5400 = 1/3 (*x*^{2})(18) (Substitute)

16200 = 18*x*^{2} (Multiply each side by 3)

900 = *x*^{2} (Divide each side by 18)

30 = *x * (Find the square root)

### Use trigonometry to find the volume of a cone

**Example 4:**

Caron made a teepee for her math project. Her teepee had a diameter of 6 feet. The angle the side of the teepee made with the ground was 65. What was the volume of the teepee? Round your answer to the nearest hundredth.

**Solution:**

To find the radius *r *of the base, use trigonometry.

tan 65^{0} = opp./adj. (Write ratio)

tan 65^{0} = *h*/3 (Substitute)

*h *= tan 65^{0 }× 3 ≈ 6.43 (Solve for *r)*

Use the formula for the volume of a cone.

*V *= 1/3 (π*r*^{2})

= 1/3 π (3^{2})(6.43)

≈ 60.57 ft^{3}

## Exercise

- A ________________________ is a pyramid having a triangular base.
- A ________________________ is a pyramid having a square base.
- Find the volume of the following solid. Round your answer to two decimal places.

- Find the volume of the following solid. Round your answer to two decimal places.

- Find the volume of the following solid. Round your answer to two decimal places.

- The volume of a pyramid is 45 cubic feet and the height is 9 feet. What is the area of the base?
- A ________________________ is a pyramid having a triangular base.

Find the value of *x*.

- A ________________________ is a pyramid having a square base.

Find the value of *x*.

- Find the volume of the following solid. Round your answer to two decimal places.
- The sky dome of the National Corvette Museum in Bowling Green, Kentucky, is a conical building. If the height is 100 feet and the area of the base is about 15,400 square feet, find the volume of air that the heating and cooling systems would have to accommodate. Round to the nearest tenth.

### Concept Map

### What have we learned

- Finding the volume of a solid.
- Use volume of a pyramid to find an unknown value.
- Apply trigonometry to find the volume of a cone.

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