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Cube Root Function

Sep 15, 2022
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Key Concepts

  • Define the features of the cube root function.
  • Identify the translation of the cube root function.
  • Solve a model problem using the cube function.
  • Calculate & compare the average rate of change of the cube root functions.

Evaluate the square root and cube root:  

1. Evaluate each expression:  

  • √25
  • √64
  • ∛27
  • ∛−64

Solution: 

  • √25=5
  • √64=8
  • ∛27=3
  • ∛−64=−4

2. Explain how ∛−27 =−3 ?  

Solution:  

parallel

(−3)3=−27,  

So, ∛-27=−3

Cube root function

The function f(x) = ∛x is the cube root function.  

Graph of cube root function

Cube root function:  
Graph of cube root function:  

Properties of cube root function

  1. Domain = All real numbers 
  2. Range = All real numbers  
  3. For f(x) = -∛x, the x – intercept and y – intercept of the graph of the function are both 0. 

Note: The graph is increasing for all values in the domain of f.  

Example:  

parallel

What are the maximum and minimum values for f(x) = ∛x over the interval −27≤x≤27?  

Solution:  

Solution:  
Graph of cube root function:  

The maximum value for f(x) = ∛x when −27≤x≤27 is 3.  

The minimum value for f(x) = ∛x when −27≤x≤27 is -3.  

Since the function is always increasing, the maximum and minimum values of the function occur at the endpoints of the given interval.   

Translation of cube root function

Example:  

The graph of g(x) = ∛x+4 compared to the graph of f(x) = ∛x

Solution:  

Translation of cube root function solution

The graph of g(x) = ∛x+4 is vertical translation of f(x) = ∛x.

When constant is added to output of the cube root function f(x) = ∛x, the graph of resulting function,

g(x) = ∛x+k, is vertical translation of the graph of f(x).  

The domain and range for both the functions are all real numbers. 

Example:  

The graph of g(x) = ∛x+6 compared to the graph of f(x) = ∛x.

Solution:  

Solution:  

The graph of g(x) = ∛x+6 is horizonal translation of f(x) = ∛x.

When constant is subtracted from input of the cube root function f(x) = ∛x. , the graph of resulting function, is horizontal translation of the graph of f. The domain and range for both the functions are all real numbers. 

Model a problem using the cube root function 

Example:  

An original clay cube contains 8 in.3 of clay. Assume that the new package will be a cube with volume x in.3. For what increases in volume would the side length increase between 1 in. and 2 in.? 

cube
Model a problem using the cube root function 

Solution:  

Let the volume of new package is x in.3

And the volume of the old package is 8 in.3

The change in side length of the cube is

f(x) = ∛x-8

Graph of (x) = ∛x-8:  

From the graph it shows that f(9)=1 and f(16)=2

So, for increases in volume between 9 and 16 in.

the side length would increase by 1 to 2 in. 

Rate of change of square root function

Example:  

For the function f(x) = ∛x-2. , how does the average rate of change from x=2 to x=4 compared to the average rate of change from x=4 to x=6?  

Solution:  

Step 1:  

Evaluate the function for the x – values that correspond to the endpoints of each interval.  

Interval: 2≤x≤4

f(2) = ∛2−2 = ∛0 =0

f(4) = ∛4−2 = ∛2 ≈1.25

Interval: 4≤x≤6

f(4) = ∛4−2 = ∛2 ≈1.25

f(6) = ∛6−2 = ∛4 ≈1.58

Step 2:  

Find the average rate of change over each interval  

From x=2 to x=4: 

f(4)−f(2)/4−2 ≈ 1.25−0/4−2 =1.25/2 ≈ 0.625

From x=4 to x=6

f(6)−f(4)/6−4 ≈ 1.58−1.256/6−4 =0.33/2 ≈ 0.165

The average rate of change of the function f(x) = ∛x−2 appears to decrease when x≥2 and as the x-values corresponding to the endpoints of the interval increase. This is consistent with the curve becoming less steep when  x≥2 and x increases.   

Example:  

Which function has the greater average rate of change over the interval 0≤x≤5 : The translation of f(x) =∛x to the right 1 unit and up 2 units, or the function g(x) = ∛x−2. 

Solution:   

The translation of f(x) = ∛x to the right 1 unit and up 2 units is h(x) = ∛x−1+2

h(0)= ∛0-1+2 = ∛−1+2 = −1+2 = 1

h(5)= ∛5-1+2 = ∛4+2 ≈ 1.58+2 = 3.58

Average rate of change = h(5)−h(0)/5−0 ≈ 3.58−1/5=2.58/5 ≈ 0.516

Given function

g(x) = ∛−2

The average rate of change of function g(x) over the interval 0 ≤ x ≤ 5 

g(0)= ∛0+2 = 0+2 =2

g(5)= ∛5+2 ≈ 1.709+2 = 3.709

Average rate of change = g(5)−g(0)/5−0 ≈ 3.709−2/5 = 1.7095 ≈ 0.341

Conclusion:  

The average rate of change of function h(x) is greater than the average rate of change of function g(x)  over the interval 0 ≤ x ≤ 5. 

Exercise

  1. Compare the graph of p(x) = ∛+5 to the graph of f(x) = ∛.
  2. Compare the graph of q(x) = ∛-2 to the graph of f(x) = ∛.
  3. Calculate the average rate of change of r(x) = ∛+2 ; 4 ≤ x ≤ 8.

Concept Summary

Concept Summary

What we have learned

  • The features of cube root function.
  • The translation of cube root function.
  • Solve a model problem using the cube function.
  • Calculate and compare the average rate of change of the cube root functions.

Comments:

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